Noble gas notation write the electron configuration for the manganese atom

The decomposition reaction of CO2(g) to produce carbon and oxygen gas consumes 462 kJ of energy. The energy levels of the produc

Semenov [28]

Answer:

higher, left

Explanation:

Given that the reaction consumes 462 kJ of energy. It means that the reaction is a endothermic reaction.

In the energy profile of the endothermic diagrams, The reactants are at a very low level as compared to the products and hence, energy is supplied to overcome this difference.

Hence, The energy levels of products are <u>higher</u> than the energy level of reactant.

Hence, already stated, heat is required by the reaction and thus heat is written to the reactant side which is to the <u>left</u> side of the equation.

3 0

3 years ago

Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta

Sergeu [11.5K]

Answer:

The half-reaction for the oxidation of the manganese in $MnCO_3(s)$ to $MnO_2(s)$ .:

$MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+$

Explanation:

$MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

Let us say the medium in which reaction is taking place is an acidic medium. And balancing in an acidic mediums done as;

Step 1: Balance all the atom beside oxygen and hydrogen atom;

$MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

Manganese and carbon are balanced.

Step 2: Balance oxygen atom adding water on the required side:

$MnCO_3+H_2O+H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

$MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

Step 3: Now balance hydrogen atom by adding hydrogen ion on the required side:

$MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+$

6 0

3 years ago

If the value of Kp for N2+3H2...2NH3 is 4/27, then for which of following reaction the value of Kp is reciprocal of above reacti

jek_recluse [69]

Answer:

C. 2O₃ ⇌ 3O₂

Explanation:

Kp is the equilibrium constant calculated from the partial pressures of a gas-phase reaction equation.

For a general gas-phase reaction aA + bB ⇌ nC + xD

the expression for the Kp = (pC)ⁿ(pD)ˣ / (pA)ᵃ(pB)ᵇ

where pA = partial pressure of A; pB = partial pressure of B; pC = partial pressure of C; pD = partial pressure of D

From the given reaction in equilibrium; N₂ + 3H₂ ⇌ 2NH₃

Kp = (pNH₃)² / (pN₂)¹ * (pH₂)³ = 4/7

(pNH₃)² / (pN₂)¹ * (pH₂)³ = (2)²/ (1)¹ * (3)³

Therefore, number of mole of reactants and products is equivalent to partial pressure.

A. 2SO₂ ⇌ O₂ + 2SO₃

pSO₂ = 2, pO₂ = 1, pSO₃ = 2,

Kp = 2²/ (2² * 1²) = 4/4 = 1

B. N₂O₄ ⇌ 2NO₂

pN₂O₄ = 1, pNO₂ = 2

Kp = 2²/1² = 4

C. 2O₃ ⇌ 3O₂

pO₃ = 2, pO₂ = 3

Kp = 3³/2² = 27/4

D. PCl₅ ⇌ PCl₃ + Cl₂

pPCl₅ = 1, pPCl₃ = 1, pCl₂ = 1

Kp = (1¹ * 1¹) / 1¹ = 1

7 0

4 years ago

Which of the following statements is true

Morgarella [4.7K]

A. you're exposed to nuclear radiation everyday

6 0

4 years ago

Saturated aqueous sodium chloride(d=1.2g/mL) is added to the following mixtures in order to dry the organic layer. Which layer i

natali 33 [55]

(a) at the bottom - high density organic compound dissolved in methylene chloride

(b) at the bottom - saturated aqueous sodium chloride

Explanation:

Sodium chloride is dissolved in water while the organic compounds are dissolved in methylene chloride. After mixing the two solutions two layers will form because water (polar molecule) will not mix with the methylene chloride (nonpolar molecule).

The layer with higher density will be at the bottom.

(a) saturated aqueous sodium chloride (d = 1.2 g/mL) - upper layer

high density organic compound dissolved in methylene chloride (d = 1.4 g/mL) - bottom layer

(b) saturated aqueous sodium chloride (d = 1.2 g/mL) - bottom layer

low density organic compound dissolved in methylene chloride (d = 1.1 g/mL) - upper layer

Learn more about:

liquids with different densities

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7 0

3 years ago