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worty [1.4K]
3 years ago
6

A catalyst is used in the chemical reaction to break down hydrogen peroxide into water and oxygen. At the end of the reaction, t

he catalyst is
Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
8 0
At the end of the reaction, the catalyst is UNCHANGED.
:)
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A student has a balloon that looks shiny like a metal and wants to perform an experiment to determine if it contains any metal.
zheka24 [161]

Answer:

Charge the balloon, hold it near an electroscope, and determine if the electroscope leaves move.

Explanation:

The gold leaf electroscope is an instrument used to detect if a body is charged. It has two gold leafs suspended from a brass stem in a vacuumed glass jar and connected to a metal cap(Toppr).

When the test body is allowed to touch the metal cap, a change in the size of the leaves shows whether the body is charged or not.

Since we are suspecting the balloon to be made up of a metal; metals can be charged. We can test if there is really a charge on the balloon by bringing it near an electroscope to see if the electroscope moves.

3 0
3 years ago
Which of the following compounds does NOT contain molecules? A. H2 B. NaCl C. CO2 D. H2O
vladimir1956 [14]
<span>NaCl is one and that is the only one that I know is for sure.

i hope this help!!!!!!!!!!</span>
3 0
3 years ago
Determination of the chemical composition of the atmospheres of the planets is carried out most effectively by what type of stud
Iteru [2.4K]
ATMOSPHERIC CHEMISTRY
7 0
3 years ago
Determine el PH y el % de disociación de una solución de ácido débil, sabiendo que se disuelven 20 gramos del ácido (masa molar=
IceJOKER [234]

Answer:

pH = 4.27. Porcentaje de disociación: 0.03%

Explanation:

El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

Donde la constante de equilibrio, Ka, es

Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]

Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:

[H⁺] = [X⁻]

[HX] es:

20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M

Reemplazando es Ka:

1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]

2.858x10⁻⁹ = [H⁺]²

5.35x10⁻⁵M = [H⁺]

pH = -log[H⁺]

<h3>pH = 4.27</h3>

El porcentaje de disociacion es [X⁻] / [HX] inicial * 100

Reemplazando

5.35x10⁻⁵M / 0.1732M * 100

<h3>0.03%</h3>
5 0
2 years ago
HELPPPP PLEASE THIS IS FOR THE CATALYSTS LAB
marishachu [46]

Answer:

the first thing you do is do your experiment then title it. then state the purpose of the experiment. included a summary of the experiment. make a list of the materials you used. present all the steps in order to make the experiment possible. note any changes to the original procedure. this is basically the steps you have to do in order to make your scientific experiment.

4 0
3 years ago
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