Answer: 0.00488K
Explanation: using the general gas equation
(P1V1)/T1 =(P2V2)/T1
Substitute
2*6/273= 3*3/T
Simplify
T= 0.00488°K
Answer:
B = A/DH – C
Explanation:
From the question given above, we obtained:
A = D • H(B + C)
Thus, we can obtain B in terms of D, H, A and C by doing the following:
A = D • H(B + C)
A = DH(B + C)
Divide both side by DH
A/DH = B + C
Subtract C from both side
A/DH – C = B + C – C
A/DH – C = B
B = A/DH – C
Answer is:
4-ethyl-1-heptene.Structure of this alkene is in Word document attached.
<span>First find main chain with longest number of carbon atoms, that is chain with seven carbon atoms and it start on the right and going up the three-carbon attachment.
Main chain has double bond between first and second carbon (</span><span>the lowest number)</span><span>, so it is 1-heptene (alkene).
</span>Substituent is on fourth carbon atom, it is alkyl group with two carbon atoms (ethyl).
Answer:
electrons fill lower energy levels first before occupying higher energy levels.
Explanation:
The Aufbau's principle describes that electrons fill lower energy levels first before occupying higher energy levels.
In writing the electronic configuration of atoms, the Aufbau's principle is one of the most important principles to consider.
It states that "sublevels with with lower energies are filled up before those with higher energies".
Sublevels do not fill up in numerical order.
Answer:
See explanation
Explanation:
According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be anomalous......It has been claimed that spin–
orbit coupling by the Russell–Saunders scheme would lower the ground state of Bi+ ..."
However, the involvement of d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.
The same argument could be extended to explain the reason why there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.
