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worty [1.4K]
3 years ago
6

A catalyst is used in the chemical reaction to break down hydrogen peroxide into water and oxygen. At the end of the reaction, t

he catalyst is
Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
8 0
At the end of the reaction, the catalyst is UNCHANGED.
:)
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How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g/mL?​
lesya692 [45]

Answer:

3.72 mol Hg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Density = Mass over Volume

Explanation:

<u>Step 1: Define</u>

D = 13.6 g/mL

54.8 mL Hg

<u>Step 2: Identify Conversions</u>

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Find</u>

13.6 g/mL = x g / 54.8 mL

x = 745.28 g Hg

<u>Step 4: Convert</u>

<u />745.28 \ g \ Hg(\frac{1 \ mol \ Hg}{200.59 \ g \ Hg} ) = 3.71544 mol Hg

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.71544 mol Hg ≈ 3.72 mol Hg

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3 years ago
What is the relationship between Ka and Kb with Kw?
lina2011 [118]
The correct answer is ...... The product of Ka and Kb equals the auto-dissociation constant for water. I know its right for sure!
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2 years ago
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What is the iupac nomenclature of diethyl methane​
grin007 [14]

Answer:

In chemical nomenclature, the IUPAC nomenclature of organic chemistry is a systematic method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC). ... IUPAC names can sometimes be simpler than older names, as with ethanol, instead of ethyl alcohol.

Explanation:

In chemical nomenclature, the IUPAC nomenclature of organic chemistry is a systematic method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC). ... IUPAC names can sometimes be simpler than older names, as with ethanol, instead of ethyl alcohol.

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3 years ago
What is Chemistry????​
prisoha [69]

Answer:

Chemistry is the scientific study of matter and its properties

Explanation:

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2 years ago
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Fe2o3(s)+3co(g)→2fe(s)+3co2(g) in a reaction mixture containing 189 g fe2o3 and 63.0 g co, co is the limiting reactant. part a c
vfiekz [6]
<span>69.3 g First, determine the molar masses involved: Atomic weight iron = 55.845 Atomic weight carbon = 12.0107 Atomic weight oxygen = 15.999 Molar mass Fe2O3 = 2 * 55.845 + 3 * 15.999 = 159.687 g/mol Molar mass CO = 12.0107 + 15.999 = 28.0097 g/mol Determine how many moles of each reactant we have Moles Fe2O3 = 189 g / 159.687 g/mol = 1.18356535 mol Moles CO = 63.0 g / 28.0097 g/mol = 2.249220806 mol For every mole of Fe2O3, we need 3 moles of CO. So let's see how many moles of Fe2O3 is consumed by dividing moles CO by 3. 2.249220806 mol / 3 = 0.749740269 mol So we'll be consuming 0.749740269 moles of Fe2O3, subtract that from what we started with 1.18356535 mol - 0.749740269 mol = 0.433825081 mol Now multiply by the molar mass of Fe2O3 0.433825081 mol * 159.687 g/mol = 69.27622574 g Rounding to 3 significant figures gives 69.3 g</span>
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3 years ago
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