Metal rusts when it oxidized around moisture.
Answer:
N2
Explanation:
We use the ideal gas equation to calculate the number of moles of the diatomic gas. Then from the number of moles we can get
Given:
P = 2atm
1atm = 101,325pa
2atm = 202,650pa
T = 27 degrees Celsius = 27 + 273.15 = 300.15K
V = 2.2L
R = molar gas constant = 8314.46 L.Pa/molK
PV = nRT
Rearranging n = PV/RT
Substituting these values will yield:
n = (202,650 * 2.2)/(8314.46* 300.15)
n = 0.18 moles
To get the molar mass, we simply divide the mass by the number of moles.
5.1/0.18 = 28.5g/mol
This is the closest to the molar mass of diatomic nitrogen N2.
Hence, the gas is nitrogen gas
Answer:
Weak bonds require less energy to form than strong bonds
Explanation:
According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.
As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.
Bond energy is defined as the amount of energy required to break the bond. If a bond is weak, it would require a low amount of energy to break it. This is also true for energy of formation, as it's the same process taking place in the opposite direction.
Answer:
The answer to your question is E = 83.2 J
Explanation:
Data
Element: Gold
Initial temperature = T1 = 5°C
Final temperature = T2 = 37°C
mass = 20 g
Specific heat = 130 J/kg°K
Process
1.- Convert temperature to kelvin
T1 = 273 + 5 = 278°K
T2 = 273 + 37 = 310°K
2.- Convert mass to kg
1000 g --------------- 1 kg
20 g --------------- x
x = (20 x 1)/1000
x = 0.02 kg
3.- Formula
E = mC(T2 -T1)
4.- Substitution
E = (0.02)(130)(310 - 278)
E = (0.02)(130)(32)
E = 83.2 J
Answer:
1.78 atm
Explanation:
From the question given above, the following data were obtained:
Mass of Cl = 355 g
Molecular weight of Cl = 70.9 g/mol
Volume (V) = 70.0 L
Temperature (T) = 30 °C
Pressure (P) =?
Next, we shall determine the number of mole in 355 g of chlorine (Cl). This can be obtained as follow:
Mass of Cl = 355 g
Molecular weight of Cl = 70.9 g/mol
Mole of Cl =.?
Mole = mass /molecular weight
Mole of Cl = 355 /70.9
Mole of Cl = 5 moles
Next, we shall convert 30 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Temperature (T) = 30 °C
Temperature (T) = 30 °C + 273 = 303 K
Finally, we shall determine the pressure of the gas as illustrated below:
Volume (V) = 70.0 L
Number of mole (n) = 5 moles
Temperature (T) = 303 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 70 = 5 × 0.0821 × 303
P × 70 = 124.3815
Divide both side by 70
P = 124.3815 / 70
P = 1.78 atm
Therefore, the pressure of the gas is 1.78 atm
