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2 years ago

Help! Solve these, please!

Mathematics

2 answers:

pychu [463]2 years ago

6 0

Answer:

1: 32-C

2: 6-A

Step-by-step explanation:

1: To find the area of a figure, multiply its height by its width.

jeyben [28]2 years ago

3 0

Answer:

The area of the triangle is 25 units

Step-by-step explanation:

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PLEASE HELP, I'VE ASKED THIS QUESTION THREE TIMES AND NO ONE WILL ANSWER SO PLEASE HELP!!!!!!!!!!!!!!!!!!!

Yuliya22 [10]

Answer:I would add 3x on both sides because it would allow you to have a positive variable saving you time and effort.

Step-by-step explanation:7=7x-9

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3 years ago

Read 2 more answers

Check whether the relation R on the set S = {1, 2, 3} is an equivalent

kozerog [31]

Answer:

$R$ isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let $S$ denote a set of elements. $S \times S$ would denote the set of all ordered pairs of elements of $S\!$ .

For example, with $S = \lbrace 1,\, 2,\, 3 \rbrace$ , $(3,\, 2)$ and $(2,\, 3)$ are both members of $S \times S$ . However, $(3,\, 2) \ne (2,\, 3)$ because the pairs are ordered.

A relation $R$ on $S\!$ is a subset of $S \times S$ . For any two elements $a,\, b \in S$ , $a \sim b$ if and only if the ordered pair $(a,\, b)$ is in $R\!$ .

A relation $R$ on set $S$ is an equivalence relation if it satisfies the following:

Reflexivity: for any $a \in S$ , the relation $R$ needs to ensure that $a \sim a$ (that is: $(a,\, a) \in R$ .)

Symmetry: for any $a,\, b \in S$ , $a \sim b$ if and only if $b \sim a$ . In other words, either both $(a,\, b)$ and $(b,\, a)$ are in $R$ , or neither is in $R\!$ .

Transitivity: for any $a,\, b,\, c \in S$ , if $a \sim b$ and $b \sim c$ , then $a \sim c$ . In other words, if $(a,\, b)$ and $(b,\, c)$ are both in $R$ , then $(a,\, c)$ also needs to be in $R\!$ .

The relation $R$ (on $S = \lbrace 1,\, 2,\, 3 \rbrace$ ) in this question is indeed reflexive. $(1,\, 1)$ , $(2,\, 2)$ , and $(3,\, 3)$ (one pair for each element of $S$ ) are all elements of $R\!$ .

$R$ isn't symmetric. $(2,\, 3) \in R$ but $(3,\, 2) \not \in R$ (the pairs in $\! R$ are all ordered.) In other words, $3$ isn't equivalent to $2$ under $R\!$ even though $2 \sim 3$ .

Neither is $R$ transitive. $(3,\, 1) \in R$ and $(1,\, 2) \in R$ . However, $(3,\, 2) \not \in R$ . In other words, under relation $R\!$ , $3 \sim 1$ and $1 \sim 2$ does not imply $3 \sim 2$ .

3 0

3 years ago

The weight of a product is normally distributed with a mean of four ounces and a variance of .25 "squared ounces." The company w

pychu [463]

Answer:

Weight=2.835

Step-by-step explanation:

See the attached picture for explanation.

8 0

2 years ago

I NEED THE ANSWER ASAP PLEASE

Natali [406]

Answer:

720$

Step-by-step explanation:

(1000+(230*24))-5800=720

8 0

2 years ago

Small juice boxes come in packages of 6. Yogurt treats come in packages of 10. Paula wants to have the exact same number of each

erastovalidia [21]

if she buys 10 of the small juice box packages and six of the yogurt treat packages then she should have an even number of both. That would be 60 of each.

8 0

3 years ago