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2 years ago

What is the product of (9+x)(9-x)

Mathematics

1 answer:

nata0808 [166]2 years ago

6 0

Answer:

81 - x^2

Step-by-step explanation:

this is a "special product," namely, the product of the sum and the difference of quantities 9 and x.

The product is the difference of two squares:

(9 + x)(9 - x) = 81 - x^2

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PLS PLS HELP :)) which series of transformations takes the graph of f(x)=2x+3 to the graph of g(x)=-2x+4?

jasenka [17]

B. Reflect the graph about the y-axis and translate one unit up

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3 years ago

Help even tho it’s multiple choice make sure you are correct... I beg you lol

kondaur [170]

Answer:

The equation of the line is:

$y=(-\frac{1}{2})x+1$

Therefore, option a is the correct answer.

Step-by-step explanation:

Given the points

(-2, 2)

(4, -1)

Finding the slope

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-2,\:2\right),\:\left(x_2,\:y_2\right)=\left(4,\:-1\right)$

$m=\frac{-1-2}{4-\left(-2\right)}$

$m=-\frac{1}{2}$

As the point-slope form of the equation of the line is

$y-y_1=m\left(x-x_1\right)$

where m is the slope

substituting the values $m=-\frac{1}{2}$ and the point (-2, 2)

$y-y_1=m\left(x-x_1\right)$

$y-2=\frac{-1}{2}\left(x-\left(-2\right)\right)$

$y-2=\frac{-1}{2}\left(x+2\right)$

$y-2=-\frac{1}{2}\left(x+2\right)$ ∵ $\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

Add 2 to both sides

$y-2+2=-\frac{1}{2}\left(x+2\right)+2$

$y=(-\frac{1}{2})x+1$

Hence, the equation of the line is:

$y=(-\frac{1}{2})x+1$

Therefore, option a is the correct answer.

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2 years ago

Help multiple choice but plz be right! Due soon

jekas [21]

Answer:

I have no info...

Step-by-step explanation:

Listen to my new playlist! https://open.spotify.com/playlist/2OmVJb8VeE0HZtU56u6IFC

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3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Nataly_w [17]

Step-by-step explanation:

$\displaystyle y = Asin(Bx - C) + D$

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{\frac{π}{3}}{3} = \frac{π}{9} \\ Period → \frac{2}{3}π$

Therefore we have our answer.

Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|$

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.

I am joyous to assist you anytime.

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2 years ago

Find the length a. a=?

algol [13]

Cosine law
a²=b²+c²-2ab*cosA

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3 years ago