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Y_Kistochka [10]
3 years ago
14

A rock is placed in a graduated cylinder to determine its volume. The following data are obtained. What is the volume of the roc

k?
Initial volume of water: 13.7 mL
Final volume of water: 28.9 mL
Mathematics
2 answers:
devlian [24]3 years ago
8 0

Answer:

The answer is 15.2 cm ^3

The other guy was wrong. (sorry if I'm to late.)

Step-by-step explanation:

yarga [219]3 years ago
7 0
Easy
when rock is in water, it takes up a certain volume, say x
so
initial+x=final volume
luckily we have final and inital
13.7ml+x=28.9ml
minus 13.7ml both sides
x=15.2ml


the volme of the rock is 15.2ml
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Answer:

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Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

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SOVA2 [1]

Answer:

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Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

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y'_p = A

y''_p = 0

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0 + 2(Ax + B) = -8x + 14

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By inspection,

2B = 14 => B = 14/2 = 7

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2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

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3 years ago
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