Answer:
162 g Fe₂O₃
Explanation:
To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.
Molar Mass (C): 12.011 g/mol
2 Fe₂O₃(s) + 3 C(s) ---> 4 Fe(s) + 3 CO₂(g)
Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)
Molar Mass (Fe₂O₃): 159.684 g/mol
18.3 g C 1 mole 2 moles Fe₂O₃ 159.684 g
-------------- x ---------------- x ------------------------- x ----------------- = 162 g Fe₂O₃
12.011 g 3 moles C 1 mole
First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation.
CH4 + 2O2 ---> CO2 + 2H20
Then using dimension analysis:
The most loosely held electrons in an atom are called valence electrons.
Answer:
Al
Explanation:
it is the longest on the graph after the other 2
Answer:
V₂ = 1.41 L
Explanation:
Given data:
Initial temperature = 35°C (35 +273.15 K = 308.15 K)
Initial volume = 1.5 L
Final temperature = 17°C (17+273.15 K = 290.15 K)
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 1.5 L × 290.15 K / 308.15 k
V₂ = 435.23 L.K / 308.15 k
V₂ = 1.41 L
