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stiks02 [169]
3 years ago
12

the value of kc for the following reaction is 0.630 at 409 K N2O4(g) --> 2NO2(g) if a reaction vessel at that temperature int

itially contains 0.0250 M NO2 and 0.0250 M N2O4, what is the concentration of NO2 at equilibrium
Chemistry
1 answer:
stealth61 [152]3 years ago
6 0

<u>Answer:</u> The concentration of nitrogen dioxide at equilibrium is 0.063 M

<u>Explanation:</u>

We are given:

Initial concentration of nitrogen dioxide = 0.0250 M

Initial concentration of dinitrogen tetraoxide = 0.0250 M

For the given chemical equation:

                        N_2O_4(g)\rightleftharpoons 2NO_2(g)

<u>Initial:</u>                0.025        0.025

<u>At eqllm:</u>         0.025-x     0.025+2x

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

We are given:

K_c=0.630

Putting values in above expression, we get:

0.630=\frac{(0.025+2x)^2}{(0.025-x)}\\\\x=-0.2013,0.019

Neglecting the negative value of 'x', because concentration cannot be negative

So, equilibrium concentration of nitrogen dioxide = (0.025 + 2x) = [0.025 + 2(0.019)] = 0.063 M

Hence, the concentration of nitrogen dioxide at equilibrium is 0.063 M

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An ionic compound is formed when there is a reaction between the elements
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An ionic compound is formed when there is a reaction between the elements whose ions are electrostatically attracted.

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A compound with the empirical formula CH 2 O has a formula mass of 180 g/mol. What is its molecular formula
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Empirical formula mass

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Molecular fornula mass:-180g/mol

  • n=Molecular formula mass/Empirical formula mass
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Molecular formula:-

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2 years ago
Draw a correct Lewis structure for XeI2 (Xe in middle, surrounded by I's ) that puts a 0 formal charge on all atoms. How many lo
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1) The Lewis structure will be:

Xe

|

I--I

In this structure, the xenon atom is surrounded by two iodine atoms, which are bonded to it through single bonds. Each iodine atom has one lone pair of electrons, for a total of 2 lone pairs on the central atom (xenon).

2) The molar mass of the gaseous compound is 0.416 g/mol.

To draw a correct Lewis structure for XeI2, we need to first count the number of valence electrons in the molecule. Xenon is a noble gas and has 8 valence electrons, while iodine has 7 valence electrons for a total of 23 valence electrons. To satisfy the octet rule and put a 0 formal charge on all atoms, we can use the following Lewis structure:

Xe

|

I--I

To find the molar mass of the gaseous compound, we can use the ideal gas law:

M = dRT/P

Where M is the molar mass, d is the density, R is the ideal gas constant, T is the temperature, and P is the pressure.

Given that the density of the gas is 0.3876 grams/142 mL = 0.002736 grams/mL, the temperature is 150 + 273 = 423 K, the pressure is 775 torr = 775/760 atm = 1.0132 atm, and the ideal gas constant is 0.08206 L·atm/mol·K.

We can calculate the molar mass as follows:

M = (0.002736 g/mL) * (0.08206 L·atm/mol·K / (1.0132 atm)) * (423 K)

M = 0.416 g/mol

Learn more about molar mass, here brainly.com/question/12127540

#SPJ4

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