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Ludmilka [50]
2 years ago
12

PLZ HELP which of the following is an example of a physical change ​

Chemistry
2 answers:
Elena L [17]2 years ago
8 0

Answer:

C.matter changes,but no new substance is formed.

lubasha [3.4K]2 years ago
7 0

Answer:

D. A piece of food turns brown and starts to smell bad is the answer because it is physical change and physical change is permanent change

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dedylja [7]
Um all? i’m confused
5 0
2 years ago
Consider the single‑step, bimolecular reaction. CH3Br+NaOH⟶CH3OH+NaBr When the concentrations of CH3Br and NaOH are both 0.120 M
GarryVolchara [31]

Answer:

Explanation:

CH₃Br+NaOH⟶CH₃OH+NaBr

It is a single step bimolecular reaction so  order of reaction is 2 , one for CH₃Br and one for NaOH .

rate of reaction = k x [CH₃Br] [ NaOH]

.008 = k x .12 x .12

k = .55555

when concentration of CH₃Br is doubled

rate of reaction = .555555 x [.24] [ .12 ]

= .016 M/s

when concentration of NaOH  is halved

rate of reaction = .555555 x [.12] [ .06 ]

= .004  M/s

when concentration of both CH₃Br and Na OH is made 5 times

rate of reaction = .555555 x .6 x .6

= 0.2 M/s

8 0
3 years ago
Can someone help me pls
BartSMP [9]

I can help. What is wrong.

7 0
2 years ago
Read 2 more answers
What is the PH of a solution with (H+) = 7.0 * 10^-12? A. 11.15 B. -11.15 C. 12.85 D -12.00
larisa [96]

Answer: A. 11.15

Explanation:

The pH of a solution is given by the formular; pH = -log [H+].

pH = - log [ 7.0 x 10 ∧-12]

     = 12 - log 7

     =  12 - 0.845

     =  11.15

8 0
3 years ago
A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to
Alex17521 [72]

137 K

The volume is constant, so you can use <em>Gay-Lussac’s Pressure-Temperature Law </em>to calculate the new temperature (you don’t have to use the number of moles).

P1/T1 = P2/T2

Solve for T2: T2= T1 x P2/P1

P1 = 1.83 atm; T1 = 122 K

P2 = 2.05 atm; T2 = ?

∴ T2 = 122 K x (2.05 atm)/(1.83 atm) = 137 K

This result makes sense. Temperature is directly proportional to pressure. You increased the pressure by about 10 %, so the temperature increased by about 10 %.

3 0
3 years ago
Read 2 more answers
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