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OleMash [197]
4 years ago
12

Answer 1-10 Need before 10:00 CN

Mathematics
1 answer:
forsale [732]4 years ago
8 0

Answer:

1. 1 4/5

2. 1 1/30

3. 2 3/20

4. 1 1/5

5. 1 13/20

6. 1 13/30

7. 1 29/60

8. 1 3/20

9. 1 7/10

10. 1 9/20

Hope this helps :)

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What is the equation of the quadratic graph with a focus of (8, −8) and a directrix of y = −6?
yarga [219]
The vertex is exactly half way between directrix and focus. In this case the vertex is (8,-7)
               (h,k)

P is the distance between the vertex and either the directrix or focus,  in this case p = 1. 

a = 1/(4p)  or 1/(4*1) or 1/4

write the equation in vertex form

y = a(x-h)^2 + k

y = 1/4(x-8)^2 -7
4 0
3 years ago
What is the length of the strip of seaweed around the outside of the sushi?
SashulF [63]
To find the circumference of a round object, you will take the diameter and multiply is by pi to get 78.5mm

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
I WILL GIVE BRAINLEST IF YOU ANSWER BOTH WITH EXPLANATION please dont let me fail :(
Lapatulllka [165]
I see grey but if that’s black okay.
2/5

You had a 2/5 chance
He had a 1/4 chance
8 0
3 years ago
Read 2 more answers
4(x-2)=4x+10
beks73 [17]

Answer:

0 solutions

Step-by-step explanation:

4(x-2)=4x+10

4x-8 = 4x+ 10

-8 = 10 (not true)

(When you have something like 6=7, 0 solutions. If it is like 6=6, infinite solutions. x=6, one solution)

8 0
3 years ago
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