Answer:
16.16.16
Step-by-step explanation:
please let me know if I'm wrong
but I learned that you don't do 4×2 you have to multiply 4 twice by itself so it would be 16 because 4×4=16
Answer:
I(7) = 22.96 W/m²
Step-by-step explanation:
Let intensity of light, be I(d) where d is distance. There must be a proportionality factor K such as
I(d) = K /d²
Now for d = 5 m I(d) = K* 1/d²
then 45 * 25 = K
K = 1125
To find the intensity when the distance from the light bulb is 7 m away
I(7) = K / 49
I(7) = 1125/49 W/m²
I(7) = 22.96 W/m²
Answer:
d. Approximate the standard normal distribution with the Student's t distribution
(0.2199 ; 0.2327)
Step-by-step explanation:
Given that :
Sample size, n = 31
Sample mean, xbar = 0.2258
Sample standard deviation, s = 0.0188
Confidence interval (C. I) :
xbar ± margin of error
Margin of Error : Tcritical * s/sqrt(n)
Degree of freedom, df = n - 1 = 31 - 1 = 30
Tcritical value :
T0.05/2, 30 = 2.042
Margin of Error = 2.042 * 0.0188/sqrt(31)
Margin of Error = 0.0068949
C. I = 0.2258 ± 0.0068949
Lower boundary : (0.2258 - 0.006895) = 0.2189
Upper boundary : (0.2258 - 0.006895) = 0.2327
(0.2199 ; 0.2327)
Step-by-step explanation:
(3x+5)-(4x²-2)-(x²-3x+1)
= 3x+5-4x²+2-x²+3x-1
=6x+6-5x²
=-5x²+6x+6