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LenaWriter [7]
3 years ago
9

A recipe for 1 gallon of fruit punch calls for 3/4 cup of orange juice. How many cups of orange juice are needed to make 8 gallo

n of fruit punch?Solve this problem any way you choose.
Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

6 cups

Step-by-step explanation:

1*8 gives you 8 gallons.

The same multiplying factor is multiplied to the cups needed too.

(3/4)*8=6

∴ 6 cups of orange juice is needed to make 8 gallon of fruit punch.

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Help me put this in order please help thanks
KATRIN_1 [288]
1. 8
2. 15
3. 2
4. 1/2
5. 3
those are the answers in order, hope this helps!
5 0
3 years ago
An electronics company produces​ transistors, resistors, and computer chips. Each transistor requires 3 units of​ copper, 2 unit
Gala2k [10]

Answer:

475 transistors, 25 resistors and 50 computer chips can be produced.

Step-by-step explanation:

Let us consider, p = Number of transistors.

                           q = Number of resistors.

                            r = Number of computer chips.

The following three linear equations according to question,

3\times p + 3\times q + 2\times r = 1600\\2\times p + 1\times q + 1\times r = 1025\\1\times p + 2\times q + 2\times r = 625

The matrix form of any system, Ax = B

Where, A = Coefficient matrix

            B = Constant vector

            x = Variable vector

A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right], x = \left[\begin{array}{ccc}p\\q\\r\end{array}\right], B = \left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]

The inverse matrix, A^{-1} can be found by using the following formula,

           A^{-1} = \frac{1}{det A}\times (C_{A}) ^{T}

Where, det A = Determinant of matrix A.

                 C_{A} = Matrix of cofactors of A

Now, applying this formula to find A^{-1};

det A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right] = 3\times(2-2)-3\times(4-1)+2\times(4-1) = -3

Here, det A\neq 0, thus the matrix is invertible.

C_{A} = \left[\begin{array}{ccc}(2-2)&-(4-1)&(4-1)\\-(6-4)&(6-2)&-(6-3)\\(3-2)&-(3-4)&(3-6)\end{array}\right] = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] \\(C_{A}) ^{T} = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] ^{T} = \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]

A^{-1} = \frac{1}{-3}\times\left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]  \\ So, x= \frac{1}{-3} \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]\times\left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]= \frac{1}{-3} \left[\begin{array}{ccc}-1425\\-75\\-150\end{array}\right] = \left[\begin{array}{ccc}475\\25\\50\end{array}\right]

So, p = 475, q = 25, r = 50.      

7 0
3 years ago
generate a continuous and differentiable function f(x) with the following properties: f(x) is decreasing at x=−5 f(x) has a loca
garik1379 [7]

Answer:

see details in graph and below

Step-by-step explanation:

There are many ways to generate the function.

We'll generate a function whose first derivative f'(x) satisfies the required conditions, say, a quadratic.

1. f(x) has a local minimum at x = -3, and

2. a local maximum at x = 3

Therefore f'(x) has to cross the x-axis at x = -3 and x=+3.

Furthermore, f'(x) must be increasing at x=-3 and decreasing at x=+3.

f'(x) = -x^2+9

will satisfy the above conditions.

Finally f(x) must be decreasing at x= -5, which implies that f'(-5) must be negative.

Check: f'(-5) = -(-5)^2+9 = -25+9 = -16 < 0  so ok.

f(x) can then be obtained by integrating f'(x) :

f(x) = integral of -x^2+9 = -x^3/3 + 9x = 9x - x^3/3

A graph of f(x) is attached, and is found to satisfy all three conditions.

7 0
3 years ago
Non example of a ratio tables
Nimfa-mama [501]

Answer:

0,4, 2,10 4,16, 6,22

Step-by-step explanation:

I really hope dis helps good luck

5 0
3 years ago
Rearrange then factorise x^2-5x+19=5x+3
Tema [17]

Answer:

x = ±4i or x = ±√-16

Step-by-step explanation:

x² - 5x + 19 = 5x + 3

x² + 16 = 0

x² = -16

x = ±√-16  (a negative square root is an imaginary number)

4 0
3 years ago
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