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Daniel [21]
3 years ago
14

List three functions of a wetland ecosystem.

Chemistry
2 answers:
Alekssandra [29.7K]3 years ago
8 0

They are particularly valuable components of the ecosystem. Much of this stems from their habitat for fish and wildlife, as well as for protecting water quality, erosion prevention, flood storage and recreation.

Their cleansing power provides natural pollution control and the way they filter and collect sediment from runoff water helps prevent mud from clogging lakes and reservoirs downstream. Wetlands help slow water flows, reducing downstream soil erosion.

Some wetlands, particularly those on floodplains and in coastal areas, function in aiding flood control by storing excess water during storm events.

Many wetlands temporarily store water, allowing it to percolate into the ground or evaporate. This can reduce peak flooding after a storm.

Wetlands shelter and feed thousands of different plants and animals, including many that are threatened and endangered. Nine of Nebraska's eleven federal endangered and threatened species use wetlands.

They also provide important winter cover for pheasants and other upland wildlife.

The ecological diversity of wetlands offers one of the most beautiful and aesthetically pleasing features of any landscape.

choli [55]3 years ago
6 0

Answer:

Water purification. Wetlands protect water quality by trapping sediments and retaining excess nutrients and other pollutants such as heavy metals.

Shoreline Stabilization.

Groundwater recharge and stream flow maintenance.

Explanation:

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What volume of 15.6M NH4OH is needed to make 500. mL of 3.00M solution?
Mariana [72]

Answer:

V₁  = 96.2 mL

Explanation:

Given data:

Initial volume of NH₄OH required = ?

Initial molarity = 15.6 M

Final molarity = 3.00 M

Final volume = 500.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of NH₄OH

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

15.6 M ×V₁  =  3.00 M×500.0 mL

15.6  M ×V₁  = 1500 M.mL

V₁  = 1500 M.mL /15.6 M

V₁  = 96.2 mL

6 0
3 years ago
.500 mol of br2 and .500 mol of cl2 are placed in a .500L flask and allowed to reach equilibrium. at equilibrium the flask was f
Tasya [4]

Answer : The value of K_c for the given reaction is, 0.36

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

Br_2(aq)+Cl_2(aq)\rightleftharpoons 2BrCl(aq)

The expression of K_c will be,

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

First we have to calculate the concentration of Br_2,Cl_2\text{ and }BrCl.

\text{Concentration of }Br_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }Cl_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }BrCl=\frac{Moles}{Volume}=\frac{0.300mol}{0.500L}=0.6M

Now we have to calculate the value of K_c for the given reaction.

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

K_c=\frac{(0.6)^2}{(1)\times (1)}

K_c=0.36

Therefore, the value of K_c for the given reaction is, 0.36

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