Its between the two hydrogen atoms (C) i hope i helped you guys out a bit.!
Answer:
Here is a similar question ; Identify the numbers from the statements above as exact or measured Sort these numbers into the proper categories. 93 g of silver, One minute, 2.20 lb ,One kilogram ,27 miles ,One yard, 100 g of sterling silver ,60 s, 1gal ,3 ft Exact Measured
Explanation:
Here is a similar question ; Identify the numbers from the statements above as exact or measured Sort these numbers into the proper categories. 93 g of silver, One minute, 2.20 lb ,One kilogram ,27 miles ,One yard, 100 g of sterling silver ,60 s, 1gal ,3 ft Exact Measured
Exact number are known from scientific research that has been proven to be true and widely acceptable or are known from true definition. for example 0 degree celsius = 273k, 1atm = 101.325 kPa
while measured numbers are not widely acceptable, they are as a result of individual measurement and discretion. A may measure the mass of a stone to be 3.5g, another person B may measure the same stone and arrive at 3.4g.
- exact numbers ; one minutes, One yard, One kilogram, 1gal, 3ft, 100g of sterling silver
- measured numbers ; 93g of silver, 2.20 lb, 27 miles
Answer:
ΔH = - 272 kJ
Explanation:
We are going to use the fact that Hess law allows us to calculate the enthalpy change of a reaction no matter if the reaction takes place in one step or in several steps. To do this problem we wll add two times the first step to second step as follows:
N2(g) + 3H2(g) → 2NH3(g) ΔH=−92.kJ Multiplying by 2:
2N2(g) + 6H2(g) → 4NH3(g) ΔH=− 184 kK
plus
4NH3(g) + 5O2(g) → 4NO(g) +6H2O(g) ΔH=−905.kJ
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2N2(g) + 6H2(g) + 5O2(g)→ 4NO(g) + 6H2O(g) ΔH = (-184 +(-905 )) kJ
ΔH = -1089 kJ
Notice how the intermediate NH3 cancels out.
As we can see this equation is for the formation of 4 mol NO, and we are asked to calculate the ΔH for the formation of one mol NO:
-1089 kJ/4 mol NO x 1 mol NO = -272 kJ (rounded to nearest kJ)
Answer:
1. Jupiter
2. Mercury
3. Venus
4. Venus
5. Jupiter
6. Neptune
7. Mercury
8. Saturn (used to be Jupiter)
