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2 years ago

Last question im going to post today. and its kinda a stupid question? but idc lol.

Mathematics

1 answer:

faltersainse [42]2 years ago

3 0

Answer:

I think the answer for table spoon is 8, 8/ and one half, 9, 10

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X |Y

Yakvenalex [24]

In all of these cases, y=x+2.

5 0

2 years ago

brad wants to open a new saving account. he finds one that returns 3% on his investment each year.Use the varibles to write a fo

Vsevolod [243]

3% is the interest so you would do 3% of the investment plus the original investment so 3%×I=z and then z+I=the answer. sorry if this didnt help I'm new and I tried my best sorry!

3 0

3 years ago

Jacob took out a loan for $5,400 at a simple interest rate of 3.5% for 6 months. How much interest did he owe?

puteri [66]

Answer:

Step-by-step explanation:

I don't trust myself so I am sorry if it is wrong

4 0

3 years ago

Read 2 more answers

ABC and CBD form a linear pair and have equal measures. Tell if ABC is acute, right, or obtuse

Murrr4er [49]

To form a linear pair means that when added, they equal 180 degrees.
but if they have equal measures....180/2 = 90...then they would both equal 90 degrees.....and 90 degrees is a right angle.
So ABC and CBD are both right angles

6 0

3 years ago

Read 2 more answers

A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip

DochEvi [55]

Answer:

The expression that represents the population of elk is: $\text{elk}(t) = 2*3^t$ . It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at $\text{elk}(0) = 2$ , then after the first year the population will be:

$\text{elk}(1) = \text{elk}(0)*3 = 2*3$

While on the second year, it'll be:

$\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2$

On the third year:

$\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3$

And so on, therefore the expression that describes the population of elk as the years passes is:

$\text{elk}(t) = 2*3^t$

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

$1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6$

The population will reach 1,458 elk in 6 years.

8 0

3 years ago