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Sveta_85 [38]
3 years ago
9

REALLY NEED HELP!!! PLZ

Mathematics
1 answer:
lbvjy [14]3 years ago
7 0
I'm confused with your worksheet. Do you have to write the improper fraction next to the Mixed number and write the Mixed number next to the improper fraction?
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7 0
3 years ago
A pilot is flying a CRJ-900 from Phoenix, Arizona, to Louisville, Kentucky. The aircraft cannot take off or land if the temperat
ioda

We need to find an inequality that represents the possible landing or take of conditions of an aircraft, the required graph and one case where the inequality will be tested.

The required inequality is -40.

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The pilot could not have taken off on June 1990, the temperature in Phoenix, Arizona.

Let the temperature be denoted by x

The temperature cannot be at or below -40^{\circ}\text{F}, so

x>-40

The temperature cannot be at or above 118^{\circ}\text{F}, so

x

The inequality will be -40.

In the graph it can be seen that all points between -40 and 118 falls in the shaded region but it will exclude the points -40 and 118.

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The temperature in June 1990 in Phoenix, Arizona was 122^{\circ} which is more than 118^{\circ}\text{F}.

Hence, the pilot could not have taken off on this day.

Learn more:

brainly.com/question/20383699

brainly.com/question/11612965

4 0
2 years ago
An astronaut with a mass of 80.70 kg is standing still on the surface of the Mars (Mars has an acceleration due to gravity of 3.
mariarad [96]

Answer:

Force, F = 68.93 pounds

Step-by-step explanation:

Given that,

Mass of the astronaut, m = 80.70 kg

Acceleration due to gravity on Mars, a=3.8\ m/s^2

The force acting on him is given by using second law of motion as :

F=m\times a

F=80.70\ kg\times 3.8\ m/s^2

F = 306.66 N

Since, 1 newton = 0.224 pound

F = 306.66 N = 68.93 pounds

So, 68.93 pounds force she exerts on the martian surface. Hence, this is the required solution.

8 0
3 years ago
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