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artcher [175]
3 years ago
9

1. Calculate the number of moles of oxygen atoms present in 1.50 mol of barium sulfate.

Chemistry
1 answer:
pochemuha3 years ago
3 0

Answer:

n_O=6.00molO

Explanation:

Hello.

In this case, since the molecular formula of barium sulfate is:

BaSO_4

Which has four oxygen atoms, we can also say that one mole of barium sulfate has four moles of oxygen; in such a way, the moles of oxygen atoms in 1.50 moles of barium sulfate are:

n_O=1.50molBaSO_4*\frac{4molO}{1molBaSO_4} \\\\n_O=6.00molO

Best regards.

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