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tresset_1 [31]
3 years ago
14

HELP ME OUTTTTTTTTTTTTTTT

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

C (The third one)

Step-by-step explanation:

Light bends when it goes through water

Refracts when hits a specific glass thing

and reflects when it goes off a mirror

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Normal distribution HELP
elena-14-01-66 [18.8K]

Answer:

0.0351478382 (To be precise)

Step-by-step explanation: Can I get brainliest? Thanks

1. Normal Distribution --> Z ~ (0,1^2)

2. Use normalcdf(lower bound, upper bound, μ, σ) function on a graphing calculator

P(Z≥103.53) = normalcdf(103.53, 1e99 [default], 80, 13)

P(Z≥103.53) ≈ 0.03

3. μ+σ ≈ 13.59% According to Z-distribution chart

80+13=93

So about 93 exceed only the top 16% (estimated answer not exact)

8 0
2 years ago
PLEASEEEEE HELPPPP IM BEGGING SOMEONE PLEASEEEEEEEE
Serjik [45]

Answer:

Step-by-step explanation:

answer is 98 degree because the relation between missing angle and 98 degree is alternate exterior angles and alternate exterior angles are always equal.

answer is 89 degree because the relation between missing angle and 89  degree is corresponding angles and corresponding angles are always equal.

5 0
3 years ago
Read 2 more answers
How is writing expressions with variables and numbers similar to writing expressions using words?
RUDIKE [14]

The expressions in which the numbers, or variables, or both, are connected by operational signs (+, - etc.) are called algebraic expressions. For example 5, 4x, a+b, x−y.

4 0
3 years ago
Read 2 more answers
Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an
Alexxx [7]

Answer:

<u>a. s.e. = 0.338</u>

<u>b. The  probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%</u>

<u>c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%</u>

d. <u>The sample mean of 62.75 would represent the 15th percentile</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

<u>s.e. = 0.338</u>

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

<u>The  probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%</u>

4.  What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

<u>p (z = -1.48) = 0.0694</u>

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

<u>The sample mean of 62.75 would represent the 15th percentile</u>

7 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
nadya68 [22]
When a negative number multiplies a negative number, it becomes positive

since it is multiplication, just multiply across, you do not need same denominators

5/8 x 16/25 = 80/200

80/200 = 40/100 = 20/50 = 2/5

2/5 is your answer

hope this helps
4 0
3 years ago
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