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Organization
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Response to a stimulus
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Answer:
Range of projectile, R
For projection above ground surface, the range of the angle of projection with respect to horizontal direction, θ, is 0° ≤ θ ≤ 90° and the corresponding range of 2θ is 0° ≤ 2θ ≤ 180°.S
hope you're looking for this.
The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.
<u>Explanation:</u>
- For the above problem, we have the case as no<n1 and n2 < n1 .
- so we have(1<1.5;1.4<1.5)To find the wavelengths of the light that is not reflected in the air.
- Since the phase changes are not common on both the surfaces/
- we have the formula, λ=2d n²/m ( where m=1,2,3,4,5...)
- solving the problem we get,
- λ5= 600 nm, λ6= 500 nm, λ7=428 nm
- The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.
Answer:
The mass of the another block is 60 kg.
Explanation:
Given that,
Mass of block M= 100 kg
Height = 1.0 m
Time = 0.90 s
Let the mass of the other block is m.
We need to calculate the acceleration of each block
Using equation of motion
![s=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Put the value into the formula
![1.0=0+\dfrac{1}{2}\times a\times(0.90)^2](https://tex.z-dn.net/?f=1.0%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%280.90%29%5E2)
![a=\dfrac{2\times1.0}{(0.90)^2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B2%5Ctimes1.0%7D%7B%280.90%29%5E2%7D)
![a=2.46\ m/s^2](https://tex.z-dn.net/?f=a%3D2.46%5C%20m%2Fs%5E2)
We need to calculate the mass of the other block
Using newton's second law
The net force of the block M
![Ma=Mg-T](https://tex.z-dn.net/?f=Ma%3DMg-T)
....(I)
The net force of the block m
![ma=T-mg](https://tex.z-dn.net/?f=ma%3DT-mg)
Put the value of T from equation (I)
![ma=Mg-Ma-mg](https://tex.z-dn.net/?f=ma%3DMg-Ma-mg)
![m(a+g)=M(g-a)](https://tex.z-dn.net/?f=m%28a%2Bg%29%3DM%28g-a%29)
![m=\dfrac{M(g-a)}{(a+g)}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7BM%28g-a%29%7D%7B%28a%2Bg%29%7D)
Put the value into the formula
![m=\dfrac{100(9.8-2.46)}{2.46+9.8}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B100%289.8-2.46%29%7D%7B2.46%2B9.8%7D)
![m=59.8\ \approx60\ kg](https://tex.z-dn.net/?f=m%3D59.8%5C%20%5Capprox60%5C%20kg)
Hence, The mass of the another block is 60 kg.