Distance = (speed) x (time)
Distance = (10 meter/second) x (2 minutes)
Distance = (10 meter/second) x (2 minutes) x (60 second/minute)
Distance = (10 x 2 x 60) (meter-minute-second / second-minute)
<em>Distance = 1,200 meters</em>
Answer:
True
Explanation:
<em>Gas</em><em> </em><em>always</em><em> </em><em>live </em><em>in </em><em>free</em><em> </em><em>state </em><em>but </em><em>some </em><em>gas </em><em>is </em><em>not </em><em>.</em><em> </em><em>We </em><em>can </em><em>said</em><em> </em><em>that</em><em> </em><em>mostly</em><em> </em><em>gas </em><em>volume</em><em> </em><em>can </em><em>be </em><em>changeable </em><em>during</em><em> </em><em>disturbing</em><em> </em><em>by </em><em>environment </em><em>situation</em><em>.</em>
The universal solvent is Water.
Answer:
B. an inverse relationship
Explanation:
Here is the complete question
Ricardo is on vacation, doing some mountain climbing. He notices that the higher he goes up a mountain, the colder he feels. He remembers his physics teacher teaching about these types of relationships. What is the type of relationship between mountain elevation and temperature? A. a positive relationship B. an inverse relationship C. a neutral relationship D. a direct relationship
Solution
It is an inverse relationship because, as Ricardo's mountain elevation increases, he feels colder. So, as his mountain elevation increases, the temperature decreases.
Since one variable decreases while the other increases, it can only be an inverse relationship.
Let h be Ricardo's mountain elevation and T his temperature. So by inverse proportionality,
h ∝ 1/T
h = k/T
hT = k = constant
So, we have an inverse relationship and B is the answer.
Answer:
0.54
Explanation:
Draw a free body diagram. There are 5 forces on the desk:
Weight force mg pulling down
Applied force 24 N pushing down
Normal force Fn pushing up
Applied force 130 N pushing right
Friction force Fnμ pushing left
Sum of the forces in the y direction:
∑F = ma
Fn − mg − 24 = 0
Fn = mg + 24
Fn = (22)(9.8) + 24
Fn = 240
Sum of the forces in the x direction:
∑F = ma
130 − Fnμ = 0
Fnμ = 130
μ = 130 / Fn
μ = 130 / 240
μ = 0.54
