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Aloiza [94]
2 years ago
9

A car travels 98 km. It takes 34.92 minutes to complete the trip. What was the average speed?

Physics
1 answer:
Dafna1 [17]2 years ago
5 0
The answer is 66,460 milliseconds
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What is the speed of a commercial jet which travels form New York to Los Angeles (4800) in 6 hours
Colt1911 [192]

Answer:

Speed = 800km}/hr

Explanation:

Given

Distance = 4800km

Time = 6hr

Required

Determine the speed of the jet

The speed is calculated as:

Speed = \frac{Distance}{Time}

Substitute 4800 km for Distance and 6hr for Time

Speed = \frac{4800km}{6hr}

Speed = 800km}/hr

<em>Hence, the speed of the commercial jet is 800km/hr</em>

8 0
2 years ago
What provides the centripetal force needed to keep Earth in orbit?
kkurt [141]
The centripetal force needed to keep earth in orbit is gravity.
3 0
3 years ago
Read 2 more answers
Bottlenose dolphins use echolocation pulses with a frequency of about 100 kHz, higher than the frequencies used by most bats. Wh
Alinara [238K]

Answer:

1. greater

2. direct

3. smaller

4. inverse

Explanation:

The speed of sound in water is greater than in air; hence for the same frequency the sound wavelength in water is <u>greater </u>than in air (for the given frequency the wavelength is in the <u>direct </u>proportion with the speed of sound).

To "see" an object via the echolocation creature needs to use sound with the wavelength <u>smaller </u>than the size of an object viewed.

That means to "see" objects of the same size dolphin and bat need to use ultrasound of the same wavelength, hence dolphin needs to use higher frequency (for the given speed of sound the wavelength is in <u>inverse </u>proportion with the frequency).

8 0
3 years ago
Describe the properties of oceanic crust
PSYCHO15rus [73]

Answer:

Not including a sedimentary cover of variable thickness and composition, the oceanic crust consists of three layers: (1) a relatively thin uppermost volcanic layer of basaltic lavas known as mid-ocean ridge basalts (MORB) erupted on the seafloor; (2) a thicker layer of more coarsely crystalline, intrusive basaltic 

6 0
2 years ago
A finite line of charge with linear charge density λ = 3.35 × 10-6 C/m, and length L = 0.808 m is located along the x axis (from
Andrews [41]

Answer: magnitude = 169.66N/C

direction = 8.6859°

Explanation:

Given from the question, we have that;

the Length of line of charge L = 0.808 m

Linear charge density λ = 3.35 × 10⁻⁶ C/m

charge q = -7.32 × 10⁻⁷ C

Coulombs force constant K = 1/(4π ε0) = 8.99 × 10⁹ N·m²/C².

NB. The picture uploaded gives a diagrammatic description of the problem.

From Pythagoras theorem we have,

tan Θ = 3.75 / (10.7-1.56)  

Θ = 22.3076 °

recall that the Electric field at point P due to the finite wire is;

È = Kλ (L / b(L+b)) Î .............. (1)

where È rep the electric field.

from equation 1, we have that  

È = 8.99 × 10⁹

where È rep the electric field.

from equation 1, we have that  

È = 8.99 × 10⁹ × 3.35 × 10⁻⁶ (0.808/ 10.7(10.7 – 0.808))

È = 0.229905 × 10³ N/C Î

recall also that the Electric field at point -P due to -q is;

È  = (8.99 × 10⁹ × 7.32 × 10⁻⁷) / ((3.75)² + (10.75-1.56)²) = 0.6742 × 10² N/C

where E = -E₁cosθÎ  + E₁sinθĴ

E = - 0.62446 ×10²Î   + 0.2562 ×10²Ĵ

The Resultant Electric charge Er is given as;

Er = 1.6771 ×10²Î + 0.2562 ×10²

Er =  [√(1.6771)² + (0.2562)² ] × 10² = 169.66 N/C

∴ Magnitude = 169.66 N/C

Having gotten the magnitude, let us find the direction;

⇒ Direction = tan Ф = 0.25621/1.6771 = 8.6859°

Direction = 8.6859°

cheers i hope this helps

7 0
3 years ago
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