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nadezda [96]
3 years ago
10

What is a negative pressure test deepwater horizon?

Physics
1 answer:
gulaghasi [49]3 years ago
6 0
It's where the pressure<span> (exerted by mud hydrostatic) in the wellbore is lower than the </span>pressure<span> exerted by the hydrocarbons. I read that in the Macondo well they had to </span>test<span> the casing (the pipe that is casing the wellbore) and cement to whether they can withstand the </span>pressure<span> of the formation (hydrocarbons layer).

</span>
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IE is the energy required to remove an electron from an atom. As atomic radius increases, the valence electrons get farther from
Bond [772]

Answer:

The bigger the atom the lesser the ability of the atom to hold on to its valence electrons.

Explanation:

Atomic radius can be looked at as the distance between the nucleus and the outermost energy level. As an atom gets bigger, the outer shell gets further and further from the positive nucleus. this means that electrons that are in the outer energy level become less held (attracted) by the nucleus because of distance and shielding of the attractive forces by the electrons in the lower energy levels. This means that as an atom becomes bigger, its ability to hold on to its outer electrons lessens.

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1. Since sleep is so important, we might wonder why people so often fail to get a sufficient amount
ziro4ka [17]

Answer: 9/10

Explanation:

because it's really important and makes you energetic

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Where can protozoa be found?
Semenov [28]
<span>Protozoa live in seas, rivers, lakes, ponds, decaying matters and soil</span>
8 0
4 years ago
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A wooden block meauring 40cm x 10cm x 5cm has a mass 850gm . find the density of wood?
Lelechka [254]

Answer:

Explanation:

Density = Mass / Volume = 850 / 40*10*5 = 0.425 g /cm^3

5 0
3 years ago
A rod of length 0.82 m, rotating with an angular speed, 4.2 rad/s, about axes that pass perpendicularly through one end, has a m
vodomira [7]

Hi there!

\large\boxed{KE =1.245 J}}

The equation of angular kinetic energy is:

KE = \frac{1}{2}Iw^2

Where:

I = moment of inertia (kgm²/s)

ω = angular speed (rad/sec)

A rod rotated about one of its endpoints has a standard moment of inertia of 1/3mR², so:

KE = \frac{1}{2}(\frac{1}{3}mL^2w^2)

KE = \frac{1}{6}mL^2w^2

Plug in the given values:

KE = \frac{1}{6}(0.63)(0.82^2)(4.2^2) = 1.245 J

4 0
3 years ago
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