A wooden block meauring 40cm x 10cm x 5cm has a mass 850gm . find the density of wood?

an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity

MatroZZZ [7]

Total displacement=150-65m=85m
Time=5s

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{Total\:Displacement}{Total\:Time}$

$\\ \rm\longrightarrow Avg\:Velocity=\dfrac{85}{5}$

$\\ \rm\longrightarrow Avg\:Velocity= 17m/s$

6 0

2 years ago

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What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1

notka56 [123]

Complete Question

Part of the question is shown on the first uploaded image

The rest of the question

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1 and q2 at x3 = -1.220 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Answer:

The net force exerted on the third charge is $F_{net}= 3.22*10^{-5} \ J$

Explanation:

From the question we are told that

The third charge is $q_3 = 55 nC = 55 *10^{-9} C$

The position of the third charge is $x = -1.220 \ m$

The first charge is $q_1 = -16 nC = -16 *10^{-9} \ C$

The position of the first charge is $x_1 = -1.650m$

The second charge is $q_2 = 32 nC = 32 *10^{-9} C$

The position of the second charge is $x_2 = 0 \ m$

The distance between the first and the third charge is

$d_{1-3} = -1.650 -(-1.220)$

$d_{1-3} = -0.43 \ m$

The force exerted on the third charge by the first is

$F_{1-3} = \frac{k q_1 q_3}{d_{1-3}^2}$

Where k is the coulomb's constant with a value $9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

substituting values

$F_{1-3} = \frac{9*10^{9}* 16 *10^{-9} * (55*10^{-9})}{(-0.43)^2}$

$F_{1-3} = 4.28 *10^{-5} \ N$

The distance between the second and the third charge is

$d_{2-3} = 0- (-1.22)$

$d_{2-3} =1.220 \ m$

The force exerted on the third charge by the first is mathematically evaluated as

$F_{2-3} = \frac{k q_2 q_3}{d_{2-3}^2}$

substituting values

$F_{2-3} = \frac{9*10^{9} * (32*10^{-9}) *(55*10^{-9})}{(1.220)^2}$

$F_{2-3} = 1.06*10^{-5} N$

The net force is

$F_{net} = F_{1-3} -F_{2-3}$

substituting values

$F_{net} = 4.28 *10^{-5} - 1.06*10^{-5}$

$F_{net}= 3.22*10^{-5} \ J$

6 0

2 years ago

Ever love a subject but then you realised the subject dosen't love you back..

viktelen [127]

Yes sirrr but at least you know now

7 0

2 years ago

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The process of digestion breaks down proteins into smaller molecules that are used to rebuild other proteins. During digestion,

Len [333]

The process of digestion breaks down proteins into smaller molecules that are used to rebuild other proteins. During digestion, proteins undergo chemical changes.

<u>Option: D</u>

<u>Explanation:</u>

Proteins are broken down into amino acids considered the foundational element. When issued, these tiny molecules can then be consumed into the bloodstream via the gut wall. An enzyme is a protein which can regulate biochemical response rate. An enzyme integrates a water molecule around the bond in enzymatic hydrolysis processes which allows it to split.

The bonds which hold together the amino acids are recognized as peptide bonds. A hydrolysis process comparable to that included in splitting up carbohydrates is required to break the peptide bonds within a protein. Enzymes identified as proteases are required for the protein to disintegrate.

7 0

3 years ago

What would you do to improve the precision of an experiment?

GenaCL600 [577]

Explanation:

Precision represents that how close the different measurements of the sample one take are to one another.

One can increase the precision in lab by paying attention to each and every detail.
Usage of the equipment properly and also increasing the sample size.
Ensuring that the equipment is calibrated properly. They should be clean and functioning. Using equipment which is not functioning correctly can cause results to swing wildly and also bits of the debris stuck to the equipment can influence the measurements of the mass and the volume.
Each measurement must be taken multiple times, especially if experiments in which combining of the substances in specific amounts is involved.

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3 years ago

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