B+c+(c-b)+(b-c). That is your expression. b 11 c 16
First, let's convert the variables to real numbers: 11+16+(16-11)+(11-16)
Now, let's solve that equation. 11+16+5+(-5)
5+(-5) cancels out, so all we have left is: 27
That is your perimeter.
Answer:
5.7
Step-by-step explanation:
pythagorean theorem
A^2 + B^2 = C^2
sub in
A^2 + 7^2 = 9^2
simplify
A^2 + 49 = 81
solve
A^2 = 32
solve further
A = 
use calculator and get:
5.65685
round and get:
<u>5.7</u>
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
Answer:
4
Step-by-step explanation:
Answer:
B
I
Step-by-step explanation:
A triangle's angles must add up to 180
68+90+x=180
158+x=180
22=x
3 and 2 must add up to 180
70+x=180
angle 2= 110
angle 2 and angle 1 have to add up to 180 as well
110+x=180
andgle 1= 70