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Yuki888 [10]
3 years ago
10

When [OH-] changes from 10-9 to 10-11 in a solution: Kw = [H+][OH-] What happens to [H+]?

Chemistry
2 answers:
victus00 [196]3 years ago
8 0
Kw is a constant number under same temperature. So when [OH-] decrease from 10^-9 to 10^-1, the [H+] will increase. So the answer is a. increases.
uranmaximum [27]3 years ago
4 0

Answer:

[H⁺] increases

Explanation:

Kw = [H⁺][OH⁻]

[OH⁻] = 10⁻⁹

Kw = 1 x 10⁻¹⁴

[H⁺] = Kw / [OH⁻] = 1 x 10⁻¹⁴ / 10⁻⁹= 10⁻⁵

[OH⁻] = 10⁻¹¹

Kw = 1 x 10⁻¹⁴

[H⁺] = Kw / [OH⁻] = 1 x 10⁻¹⁴ / 10⁻¹¹= 10⁻³

As the concentration of OH⁻decreases, the concentration of H⁺ increases.

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