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Evgen [1.6K]
3 years ago
9

According to the oxygen-hemoglobin dissociation curve, PO2 in the lungs of 100 mm Hg results in Hb being 98% saturated. At high

altitude, there is less O2. At a PO2 in the lungs of 80 mm Hg, Hb would be ________ saturated.
Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

Hb would be 78.4% saturated.

Explanation:

This problem can be solved by using simple unitary method.

At 100 mm Hg pressure of oxygen, Hb is saturated by 98%

So, at 1 mm Hg pressure of oxygen, Hb is saturated by \frac{98}{100}%

Hence, at 80 mm Hg pressure of oxygen, Hb is saturated by \frac{98\times 80}{100}% or 78.4%

Therefore, at 80 mm Hg pressure of oxygen in the lungs, Hb would be 78.4% saturated.

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dolphi86 [110]

Answer:

7.7056 x 10^23

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3 years ago
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Dvinal [7]

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Explanation:

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6 0
3 years ago
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

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8 0
3 years ago
What is the charge of an electron<br> A. -1<br> B. 0<br> C. +1<br> D. +2
Gelneren [198K]

Answer:

A

Explanation:

I believe it is negative 1.

6 0
3 years ago
NEED ANSWER FAST!
lorasvet [3.4K]

Answer:

B

Explanation:

Molarity = 0.010M

Volume = 2.5L

Applying mole-concept,

0.010mole = 1L

X mole = 2.5L

X = (0.010 × 2.5) / 1

X = 0.025moles

0.025moles is present in 2.5L of NaOH solution.

Molar mass of NaOH = (23 + 16 + 1) = 40g/mol

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass = 0.025 × 40

Mass = 1g

1g is present in 2.5L of NaOH solution

6 0
3 years ago
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