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nexus9112 [7]
3 years ago
9

What is the range of the function y=3^x x>0 R y<0 y>0

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0

Answer:

The range is  y > 0

Step-by-step explanation:

3^x is always greater than 0 and cannot be negative   unless x is not real

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The camera cost $540 if the sales tax is 7.2% what is the tax change and the total cost?
suter [353]

Answer:

$75 ?

Step-by-step explanation:

If this is wrong super sorry :)

7 0
2 years ago
Which is the decimal expansion of StartFraction 7 Over 22 EndFraction? ModifyingAbove 0. 318 with bar 0. 3ModifyingAbove 18 with
Lena [83]

The answer to the question will be 0. 3 Modifying Above 18 with bar

<h3>What will be the decimal expansion of 7 over 22? </h3>

When we divide 7 by 22 we will get 0.3181818..........

Here 3 is not repeating but 18 is repeating again and again

So it is a Non-terminating repeating number

Thus the answers to the question will be 0. 3 Modifying Above 18 with bar

To know more about Non terminating repeating numbers follow

brainly.com/question/17636098

8 0
2 years ago
What is the value of x?
V125BC [204]
The value of X is 1
7 0
3 years ago
Find cube root of 175616 ??​
Tpy6a [65]

Answer:

56

Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

Step III : Group the factors in 3 in such a way that each number of the group is same

Step IV : Take one factor from each group

Step V : Find the product of the factors obtained in step IV. This product is the required cube root

Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

please mark me as a brainlist

3 0
3 years ago
Solve the inequality –3(r – 5) + 7 &gt; 28.
docker41 [41]

Answer: r<-2

Step-by-step explanation:

-3(r-5)+7>28

-3(r-5)+7-7>28-7

-3(r-5)>21

3(r-5)/3 < -21/3

r-5<-7

r-5+5<-7+5

r<-2

5 0
3 years ago
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