Answer:
43.7
Explanation:
Volume of gas = 1.00L
Time = 12 hours
Decrease in 1 balloon = 0.200L
Decrease in second balloon = 0.0603L
R1 = rate at which helium diffuses= 0.20/12= 0.0166
R2 = rate at which heavier gas diffuses = 0.0693/12 = 0.00502
Using grahms law
R1²/R2² = m/4
= 0.0166²/0.00502² = m/4
= 10.935 = m/4
When we cross multiply
m is the molar mass of heavier gas = 43.73
Molecular hydrogen (H2)
Hydrogen (H2O2)
Nirous Oxide (N2O)
Methane (CH4)
I am so sorry if this is incorrect I did it a long time ago!
Answer:
Friction of wind against the ocean surface
Answer:
No effect will be observed since C is not included in the equilibrium expression.
Explanation:
Let's consider the following reaction.
CO₂(g) + C(graphite) ↔ 2 CO(g)
The equilibrium constant (Kc) is the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
Kc only includes gases and aqueous species (not liquids or solids).
![Kc=\frac{[CO]^{2}}{[CO_{2}]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BCO%5D%5E%7B2%7D%7D%7B%5BCO_%7B2%7D%5D%7D)
As we can see, C is a solid and is not included in the equilibrium expression, so adding some C would have no effect on it.
Answer:
5.46
Explanation:
From the question,
pH this can be defined as the acidity or alkalinity of a solution.
The expression for pH is given as
pH = -log(H⁺)...................... Equation 1
Where H⁺ = Hydrogen ion of HCL
Given: H⁺ = 3.5×10⁻⁶ M
Substitite this value into equation 1
pH = -log(3.5×10⁻⁶)
pH = 5.46
Hence the pH of HCl is 5.46
