Answer: The rate will increase by a factor of 9.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![2NO(g)+2H_2(g)\rightarrow N_2(g)+2H_2O(g)](https://tex.z-dn.net/?f=2NO%28g%29%2B2H_2%28g%29%5Crightarrow%20N_2%28g%29%2B2H_2O%28g%29)
Given: Order with respect to
= 2
Order with respect to
= 1
Thus rate law is:
![Rate=k[NO]^2[H_2]^1](https://tex.z-dn.net/?f=Rate%3Dk%5BNO%5D%5E2%5BH_2%5D%5E1)
k= rate constant
It is given that the initial concentration of NO is tripled while all other factors stayed the same
![Rate'=k[3\times NO]^2[H_2]^1](https://tex.z-dn.net/?f=Rate%27%3Dk%5B3%5Ctimes%20NO%5D%5E2%5BH_2%5D%5E1)
![Rate'=k[3]^2[NO]^2[H_2]^1](https://tex.z-dn.net/?f=Rate%27%3Dk%5B3%5D%5E2%5BNO%5D%5E2%5BH_2%5D%5E1)
![Rate'=k\times 9[NO]^2[H_2]^1](https://tex.z-dn.net/?f=Rate%27%3Dk%5Ctimes%209%5BNO%5D%5E2%5BH_2%5D%5E1)
![Rate'=9\times Rate](https://tex.z-dn.net/?f=Rate%27%3D9%5Ctimes%20Rate)
Thus the rate will increase by a factor of 9.
Answer:
a. Molarity= ![M =2.1x10^{-1}M](https://tex.z-dn.net/?f=M%20%3D2.1x10%5E%7B-1%7DM)
b. Molality= ![m=2.0x10^{-1}m](https://tex.z-dn.net/?f=m%3D2.0x10%5E%7B-1%7Dm)
Explanation:
Hello,
In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:
![M=\frac{n_{solute}}{V_{solution}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L} =2.1x10^{-1}M](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bn_%7Bsolute%7D%7D%7BV_%7Bsolution%7D%7D%20%3D%5Cfrac%7B3.9g%2A%5Cfrac%7B1mol%7D%7B93g%7D%20%7D%7B0.2L%7D%20%3D2.1x10%5E%7B-1%7DM)
Moreover, the molality:
![m=\frac{n_{solute}}{m_{solvent}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L*\frac{1.05kg}{1L} } =2.0x10^{-1}m](https://tex.z-dn.net/?f=m%3D%5Cfrac%7Bn_%7Bsolute%7D%7D%7Bm_%7Bsolvent%7D%7D%20%3D%5Cfrac%7B3.9g%2A%5Cfrac%7B1mol%7D%7B93g%7D%20%7D%7B0.2L%2A%5Cfrac%7B1.05kg%7D%7B1L%7D%20%7D%20%3D2.0x10%5E%7B-1%7Dm)
Best regards.
A particle with jagged, rough ends has a high rate of deposition.
A bond involves the swapping of electrons, transfer, etc, like a covalent or ionic bond.
An intermolecular interaction isn't necessarily a bond, but rather a charge that keeps atoms near each other. For example, a glass can swell at the top without overflowing or you can have a meniscus in your graduated cylinder because water sticks to the sides. These are intermolecular interactions, not bonds. An example are London Dispersion Forces. These are intermolecular interactions that control the melting and boiling temperatures of compounds.
Think, if molecules didn't interact with each other, what's holding them together? Why don't they just fly off? Because they interact with each other, we have the states of matter! We need so much heat to give them energy, just so that their own motion can break these forces and cause them to change state.
also i haven't taken chemistry so idk what im doing oops