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Lilit [14]
3 years ago
5

Can anyone help me understand how to evaluate the limit of this complex fraction?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

-1/9

Step-by-step explanation:

\lim_{x \to 3} \frac{1/x-1/3}{x-3}

For simplicity, let's multiply top and bottom by 3x:

\lim_{x \to 3} \frac{3-x}{3x(x-3)}

Factor out a -1:

\lim_{x \to 3} \frac{-(x-3)}{3x(x-3)}

Divide top and bottom by x−3:

\lim_{x \to 3} \frac{-1}{3x}

Evaluate the limit:

\frac{-1}{3(3)}\\-\frac{1}{9}

It's important to note that the function doesn't exist at x = 3.  As x <em>approaches</em> 3, the function <em>approaches</em> -1/9.

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NEED HELP ON ALL OF THESE PLEASE
tangare [24]

Answer:

1) 2670m^2

2) 4718 in^2

3) 4730 ft^2

4) 7900cm^2

5) 11 542mm^2

6) 3740m^2

7) 6374m^2

8) 2824 ft^2

9) 6004mm^2

Step-by-step explanation:

Area of a rectangular prism = 2wl + 2lh + 2hw

Where,

w = width

l = length

h = height

1) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 10m; l = 31m; w = 25m

Area = 2(25m)(31m) + 2(31m)(10m) + 2(10m)(25m)

= 2(775m^2) + 2(310m^2) + 2(250m^2)

= 1550m^2 + 620m^2 + 500m^2

= 2670m^2

2) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 21 in; l = 35 in; w = 29 in

Area = 2(29in)(35in) + 2(35in)(21in) + 2(21in)(29in)

= 2(1015in^2) + 2(735in^2) + 2(609in^2)

= 2030in^2 + 1470in^2 + 1218in^2

= 4718 in^2

3) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 19 ft; l = 39ft; w = 28ft

Area = 2(28ft)(39ft) + 2(39ft)(19ft) + 2(19ft)(28ft)

= 4730 ft^2

4) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 24,cm; l = 49cm; w = 38cm

Area = 2(38cm)(49cm) + 2(49cm)(24cm) + 2(24cm)(38cm)

= 7900cm^2

5) 11 542mm^2

6) 3740m^2

7) 6374m^2

8) 2824 ft^2

9) 6004mm^2

Note : Kindly follow the same process for the remaining questions, you'd get their correct answers. I can't finish up due to time constraints. However, you may send me a direct message for the remaining answers. Thank you.

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