reflection and translation.
Given:
The different transformation in the options.
To find:
The transformation that would result in the perimeter of a triangle being different from the perimeter of its image.
Solution:
In option 1,
It represents reflection across the line y=x.
In option 2,
It represents reflection across the x-axis.
In option 3,
It represents dilation by scale factor 4 and the center of dilation is at origin.
In option 4,
It represents translation 2 units right and 5 units down.
We know that the reflection and translation are rigid transformations, It means the size and shape of the figure remains the same after transformation.
So, the perimeter of the figure and its image are same in the case of reflection and translation.
But dilation is not a rigid transformation. In dilation, the figure is similar to its image. So, the perimeter of the figure and its image are different in the case of dilation.
Therefore, the correct option is 3.
Answer:
Step-by-step explanation:
Given (64 y Superscript 100 Baseline) Superscript one-half.
Let us write it into an equation.
Apply radical rule: ![\sqrt[n]{a}=a^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
and 
![\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cleft%2864%20y%5E%7B100%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%26%3D%5Csqrt%5B2%5D%7B64%20y%5E%7B100%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%20y%5E%7B50%7D%20y%5E%7B50%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%5Cleft%28y%5E%7B50%7D%5Cright%29%5E%7B2%7D%7D%20%5C%5C%26%3D8%20y%5E%7B50%7D%5Cend%7Baligned%7D)
Hence, is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.
Subtract 5 from both sides
so now it should be like this
-3p=-8p+5
Now add 8p to both sides
now it should look like this
5p=5
now divide
5/5= 1
sp p=1
In this particular case the 2 numbers can be 17 and 34, in both cases, the GCF would be 17.
Answer:
(f + g)(x) = 5x² + 2x - 5
Domain: All real numbers
(f - g)(x) = -5x² + 2x - 5
Domain: All real numbers
(fg)(x) = 10x³ - 25x²
Domain: All real numbers
(f/g)(x) = 
Domain: (negative infinity, 0)U(0, positive infinity)
Step-by-step explanation:
For f + g, we are simply adding the 2 together
<em>Domain: All values of x work, as any value x outputs any value y</em>
For f - g, we are simply subtracting the 2 together
<em>Domain: All values of x work, as any value x outputs any value y</em>
For f times g, we are simply multiplying (distributing) the 2 together
<em>Domain: All values of x work, as any value x outputs any value y</em>
For f divided by g, we are simply dividing (fraction) the 2 together
<em>Domain: All values except for 0 work (undefined error), so asymptote at x = 0</em>
