Question

Can anyone help me understand how to evaluate the limit of this complex fraction?

Answer 1

Answer:

-1/9

Step-by-step explanation:

$\lim_{x \to 3} \frac{1/x-1/3}{x-3}$

For simplicity, let's multiply top and bottom by 3x:

$\lim_{x \to 3} \frac{3-x}{3x(x-3)}$

Factor out a -1:

$\lim_{x \to 3} \frac{-(x-3)}{3x(x-3)}$

Divide top and bottom by x−3:

$\lim_{x \to 3} \frac{-1}{3x}$

Evaluate the limit:

$\frac{-1}{3(3)}\\-\frac{1}{9}$

It's important to note that the function doesn't exist at x = 3.  As x approaches 3, the function approaches -1/9.