Question

How many moles of SnF₂ will be produced along with 48 grams of H₂? *

Answer 1

Answer: 24 moles of $SnF_2$ are produced.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$    

${\text{Moles of} H_2}=\frac{48g}{2g/mol}=24moles$

$Sn+2HF\rightarrow SnF_2+H_2$

According to stoichiometry :

1 mole of $H_2$ is accompanied with = 1 mole of $SnF_2$

Thus 24 moles of $H_2$  is accompanied with =$\frac{1}{1}\times 24=24moles$  of $SnF_2$

Thus 24 moles of $SnF_2$ are produced.