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fredd [130]
3 years ago
12

What occurs if two objects at different temperatures are in contact?

Chemistry
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

If two objects at different temperatures are brought in contact with each other, energy is transferred from the hotter to the colder object until equilibrium is reached and the bodies reach thermal equilibrium (i.e., they are at the same temperature). ... Heat is a form of energy, whereas temperature is not.

Explanation:

Hope this helps~! :D

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For the chemical equation SO 2 ( g ) + NO 2 ( g ) − ⇀ ↽ − SO 3 ( g ) + NO ( g ) the equilibrium constant at a certain temperatur
MakcuM [25]

Answer:

Moles of NO₂ = 0.158

Explanation:

                         SO 2 ( g ) + NO 2 ( g ) ⇄  SO 3 ( g ) + NO ( g )

              According to the law of mass equation

                                     

                                       K_{c} = \frac{[SO_{3} ][NO]}{[SO_{2}][NO_{2}  ]}

                              ⇒   3.10 = \frac{(1.00)(1.00)}{(2.30) [NO_{2} ]}    At equilibrium [SO₃] = [NO]

                              ⇒ [NO₂] = \frac{1}{6.3}

                              ⇒ [NO₂] = 0.158

So. number of moles of NO₂ at equilibrium added = 0.158

8 0
3 years ago
Why are scientific models important in the study of science?
DochEvi [55]
They help scientists understand complex ideas and objects that aren’t easy to handle.
3 0
3 years ago
13. An aerosol spray can of deodorant with a volume of 0.410 L contains 3.0 g of propane gas (CH3) as propellant. What is the pr
qaws [65]

Answer: The pressure in the can is 4.0 atm

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = ?

V = Volume of gas = 0.410 L

n = number of moles = \frac{\text {given mass}}{\text {Molar mass}}=\frac{3.0g}{44.1g/mol}=0.068mol

R = gas constant =0.0821Latm/Kmol

T =temperature =20^0C=(20+273)K=293K

P=\frac{nRT}{V}

P=\frac0.068mol\times 0.0820 L atm/K mol\times 293K}{0.410L}=4.0atm

Thus the pressure in the can is 4.0 atm

8 0
2 years ago
Question 5(Multiple Choice Worth 3 points)
Katarina [22]

Answer:

\sqrt{ | {o2}^{2} | }  \times \frac{?}{?}  \sqrt[?]{?}  \times \frac{?}{?}  \sqrt[ |?| ]{?}  \sqrt{?}  \times  \frac{?}{?}

Explanation:

exactly

4 0
3 years ago
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
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