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Norma-Jean [14]

2 years ago

6

10. Composite volcanoes

2 answers:

BartSMP [9]2 years ago

6 0

Answer:

Composite volcanoes. ... They are typically steep-sided, symmetrical cones of large dimension built of alternating layers of lava flows, volcanic ash, cinders, blocks, and bombs and may rise as much as 8,000 feet above their bases.Muh. 28, 1432 AH

lys-0071 [83]2 years ago

5 0

The answer is probably A

Explanation:
It cannot be B as it has broader base, cannot be C as it gets steeper as you approach the top and they are very common. (Also, it is called stratovolcano which has layers)

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What are the rows of the periodic table called?

Sergio039 [100]

Answer:

"The elements are arranged in seven horizontal rows,called periods or series,and 18 vertical columns,called Groups."

Explanation:

Risk*

4 0

3 years ago

What is the molar concentration of a solution prepared by dissolving 8.63 g of Ba(NO3)2 (molar mass = 261.35 g/mol) to a total v

PilotLPTM [1.2K]

Answer:

我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈

Explanation:

我實際上不知道我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈我實際上不知道答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈答案，我只是為了點數而這樣做，哈哈，祝你好運哈哈

7 0

3 years ago

A gas cylinder initially contains 463 L of gas at a pressure of 159 atm. If the final volume of gas is 817 L, what is the final

Agata [3.3K]

Answer:

The final pressure is 90.1 atm.

Explanation:

Assuming constant temperature, we can solve this problem by using <em>Boyle's Law</em>, which states:

P₁V₁=P₂V₂

Where in this case:

P₁ = 159 atm

V₁ = 463 L

P₂ = ?

V₂ = 817 L

We <u>input the given data</u>:

159 atm * 463 L = P₂ * 817 L

And <u>solve for P₂</u>:

P₂ = 90.1 atm

The final pressure is 90.1 atm.

6 0

3 years ago

Please select the word from the list that best fits the definition

sammy [17]

Pretty sure it’s ,B. Microscope!

8 0

3 years ago

If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra

docker41 [41]

Answer :

(a) The moles of $CrO_3$ is, 1.5 moles.

(b) The number of oxygen atoms are, $27.099\times 10^{23}$

(c) The mass of oxygen is, 72 grams.

Explanation : Given,

Mass of $CrO_3$ = 150 g

Molar mass of $CrO_3$ = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of $CrO_3$ .

$\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles$

The moles of $CrO_3$ is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

In $CrO_3$ , there are 1 atom of chromium and 3 atoms of oxygen.

According to the mole concept,

1 mole of $CrO_3$ contains $3\times 6.022\times 10^{23}$ number of oxygen atoms.

So, 1.5 mole of $CrO_3$ contains $1.5\times 3\times 6.022\times 10^{23}=27.099\times 10^{23}$ number of oxygen atoms.

The number of oxygen atoms are, $27.099\times 10^{23}$

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of $CrO_3$ contains 3 moles of oxygen

So, 1.5 mole of $CrO_3$ contains $1.5\times 3=4.5$ moles of oxygen

$\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}$

$\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g$

The mass of oxygen is, 72 grams.

3 0

3 years ago