Answer:
ΔH₁₂ = -867.2 Kj
Explanation:
Find enthalpy for 3H₂ + O₃ => 3H₂O given ...
2H₂ + O₂ => 2H₂O ΔH₁ = -483.6 Kj
3O₂ => 2O₃ ΔH₂ = + 284.6 Kj
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3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O (multiply by 3 to cancel O₂)
6H₂ + 3O₂ => 6H₂O ΔH₁ = 3(-483.6 Kj) = -1450.6Kj
2O₃ => 3O₂ ΔH₂ = -284.6Kj (reverse rxn to cancel O₂)
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6H₂ + 2O₃ => 6H₂O ΔH₁₂ = -1735.2 Kj (Net Reaction - not reduced)
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divide by 2 => target equation (Net Reaction - reduced)
3H₂ + O₃ => 3H₂O ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj
There are four main factors that can affect the reaction rate of a chemical reaction:
Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. ...
Physical state of the reactants and surface area. ...
Temperature. ...
Presence of a catalyst.
please make me brainlist answer
Volume is the amount of space occupied in a object
Answer:
<em>415.15 mL</em>
Explanation:
To solve the statement, you can use the law of Charles - Gay Lussac, which states that "<em><u>the volume of gas is directly proportional to its temperature at constant pressure</u></em>." Mathematically:
You can calculate the volume V₂ Clearing it from the equation and replacing the values granted by the statement to perform the calculation:
V₂ = V₁ x T₂ / T₁ = 222 mL x 56.1 ° C / 30.0 ° C = 415.15 mL
Therefore, <em>the gas at 56.1 ° C will occupy a volume of 415.15 mL</em>
Oxygen is the only element in the list.
