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faust18 [17]
3 years ago
9

In the Copper Plating Solution lab, you placed copper (Cu) pennies in vinegar. Vinegar is a weak acid with hydrogen ions (H+). W

hen you put the pennies in the vinegar, you should have observed small gas bubbles. What were these bubbles composed of, and how did they form
Physics
1 answer:
PolarNik [594]3 years ago
6 0
Bubbles came off from the copper pennies are hydrogen gas. There many free hydrogen ions in an acid like vinegar. And because of the chemical reaction between the copper and the vinegar, many hydrogen ions joined together to form hydrogen gas. 
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Corey runs a 100-meter race. 7 seconds after the race started Corey is 45 meters from the starting line and reaches his max spee
RUDIKE [14]

Answer:

  • Corey's max speed is 7 \frac{m}{s}
  • the distance Corey's covers in z seconds is 7 \frac{m}{s} * z \ s
  • d (z) = 45 m + 7 \frac{m}{s} * z
  • d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

Explanation:

<h3>Corey's max speed</h3>

For constant speed, we know:

v=\frac{distance}{time}

The distance between the 80 meters and the 45 meters is:

distance = 80 m - 45 m = 35 m

and the time it took to reach the 80 meter will be:

time = 12 s - 7 s = 5 s

So, Corey's max speed is

v_{max}=\frac{35 m}{5 s} = 7 \frac{m}{s}

<h3>How far runs Corey</h3>

As the velocity of Corey's is v_{max}, the distance Corey's covers in z seconds is

distance = v_{max} * z \ s

distance = 7 \frac{m}{s} * z \ s

<h3>What is Corey's distance from the starting line</h3>

At time 7 + z seconds the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (z) = 45 m + v_{max} * z

d (z) = 45 m +7 \frac{m}{s} * z

At time x ( x greater or equal to 7 seconds) the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (x) = 45 m + v_{max} * (x-7 s)

d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

4 0
2 years ago
A rocket is launched from rest and moves in a straight line at 30.0 degrees above the horizontal with an acceleration of 35.0 m/
klemol [59]

Answer:

t = 123.59s

Explanation:

For the launch pad section:

Vf = Vo + a*t  where Vo=0.

Vf = 35*25 = 875m/s

The distance traveled during the launch:

d = Vo*t+\frac{a*t^2}{2} = 0+\frac{35*25^2}{2} = 10937.5m

Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.

\Delta Y = Vo*sin(30)*t - \frac{g*t^2}{2}

-d*sin(30) = Vo*sin(30)*t - \frac{g*t^2}{2}  where d= 10937.5m; Vo=875m/s.

Solving for t:

t1 = -11.093s   t2 = 98.59s

So, the total time of flight will be:

t_{total} = t_{launch}+t_{projectile}=25+98.59 = 123.59s

6 0
3 years ago
How can energy crisis be aberted?​
omeli [17]

Answer:

Try and depend more on renewable energy sources. Use products that are more energy efficient. Make use of lighting control measures. Maintain climate change

6 0
2 years ago
What type of elastic force is present in the strings on a guitar?
jeyben [28]
B) Tension , is the correct answer
4 0
2 years ago
True or False? Energy is matter.<br><br> 1. False<br><br> 2. True
andriy [413]

Answer:

False because it has no mass.

Explanation:

7 0
2 years ago
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