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faust18 [17]
3 years ago
9

In the Copper Plating Solution lab, you placed copper (Cu) pennies in vinegar. Vinegar is a weak acid with hydrogen ions (H+). W

hen you put the pennies in the vinegar, you should have observed small gas bubbles. What were these bubbles composed of, and how did they form
Physics
1 answer:
PolarNik [594]3 years ago
6 0
Bubbles came off from the copper pennies are hydrogen gas. There many free hydrogen ions in an acid like vinegar. And because of the chemical reaction between the copper and the vinegar, many hydrogen ions joined together to form hydrogen gas. 
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Rudik [331]

The half-meter rule (easy math) is 0.5 meters or 50 centimeters since a meter is 1 meters long, which is equivalent to 100 centimeters. Therefore, we shall apply the 50 cm rule.

A 50 cm rule's center of mass is now 25 cm away.

Additionally, according to the data, the object is pivoted at 15 cm, while the 40 g object is hung at 2 cm from the rule's beginning. Using a straightforward formula, we can compare the two situations: the distance from the pivot to the center of the mass times the mass of the 40 g object divided by 2 cm must equal the distance from the pivot to the center of the mass times mass of the 10 x g object

The result of the straightforward computation must be 52g.

Most simplified version:

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2 years ago
Which part, A or B, captures, amplifies, and demodulates radio waves? _____
olga_2 [115]

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A metal bar, pivoted at one end, oscillates freely in the absence of a magnetic field. But when it oscillates between the poles
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Explanation:

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F=G \frac{ m_{1} m_{2} }{ r^{2}}
We can see from this formula that gravitational force is <span>inversely proportional to the square of the distance between bodies.
The electrostatic force between two charges is Coulombs force. We can write it down like this: 
</span>F= k_{e} \frac{ q_{1} q_{2} }{ r^{2}}
This force is also inversely proportional to the square of the distance between interacting particles.
The nuclear force is a little bit more complicated. It can be expressed using the so-called Yukawa potential, which has the following form:
V_{y} =- g^{2} \frac{ e^{-ur} }{r}
This interaction does not follow the inverse-square law.
The final answer should be 8.
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