Question

What is the gravitational field strength at a distance of 60.0 km above the surface of the earth

Answer 1

Answer:

g=9.64m/s^2.

Explanation:

Gravitational field strength (in other words, gravitational acceleration) is given as follows:g=GMR2g=R2GM​where G=6.674×10−11m3kg⋅s2G=6.674×10−11kg⋅s2m3​ is the gravitational constant, M=5.972×1024kgM=5.972×1024kg is the mass of the Earth, and R=6.371×106m+0.06×106m=6.431×106mR=6.371×106m+0.06×106m=6.431×106m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).