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3 years ago

Consider the hydrocarbon below.

2 answers:

4 0

It is an Alkene because it has a double bond, so it’ll have “ene” at the end. The simplest Alkene has 2 carbons.

2 carbons = “eth”

Look at that! Two carbons! It must be “ethene”

Pachacha [2.7K]3 years ago

3 0

Answer: ethene

Explanation:

The representation of the hydrocarbon is:

H        H
\       /
C = C
/        \
H         H

So, the double C bond means it is an alkene.

The number of carbon atoms in the molecule is named with the proper prefix:

propa - is used for 3 carbon atoms
penta - is used for 5 carbon atoms
but - is used for 4 carbon atoms
etha - is use for 2 carbon atoms.

Therefore that alkene is name ethene

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The maximum solubility of Ag2CO3 in 0.02<br>M Na2CO3 is (Ksp of<br>Ag2003 is 8 x 10-12)<br>

Anna007 [38]

The maximum solubility of Ag₂CO₃ = = 1 x 10⁻⁵

<h3>Further explanation</h3>

Given

0.02 M Na₂CO₃

Ksp of Ag₂CO₃ is 8 x 10⁻¹²

Required

The solubility of Ag₂CO₃

Solution

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s 2s s

s = solubility

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Ksp Ag₂CO₃ = (2s)².s

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8 x 10⁻¹² = [2s]² [0.02]

8 x 10⁻¹² = 4s² [0.02]

4s² = 8 x 10⁻¹² / 2 × 10⁻²

4s² = 4 x 10⁻¹⁰

s² = 1 x 10⁻¹⁰

s = √1 x 10⁻¹⁰

s = 1 x 10⁻⁵

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<h3>Percent yield</h3>

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More on percent yield can be found here: brainly.com/question/17042787

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