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RSB [31]
3 years ago
15

Consider the hydrocarbon below.

Chemistry
2 answers:
Ket [755]3 years ago
4 0
It is an Alkene because it has a double bond, so it’ll have “ene” at the end. The simplest Alkene has 2 carbons.

2 carbons = “eth”

Look at that! Two carbons! It must be “ethene”
Pachacha [2.7K]3 years ago
3 0
Answer: ethene

Explanation:

The representation of the hydrocarbon is:

H        H
  \       /
  C = C
  /        \
H         H

So, the double C bond means it is an alkene.

The number of  carbon atoms in the molecule is named with the proper prefix:

propa - is used for 3 carbon atoms
penta - is used for 5 carbon atoms
but - is used for 4 carbon atoms
etha - is use for 2 carbon atoms.

Therefore that alkene is name ethene
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Select the correct value for the indicated bond angle in each of the following compounds: O-S-O angle of SO2 F-B-F angle of BF3
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Answer:

(A) O-S-O bond angle of SO₂ molecule = 119°

(B) F-B-F bond angle of BF₃ molecule = 120°

(C) Cl-S-Cl bond angle of SCl₂ molecule = 103°

(D) O-C-O bond angle of CO₂ molecule = 180°

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(F) H-C-H bond angle of CH₄ molecule = 109.5°

Explanation:

Bond angle refers to the angle between two adjacent chemical bonds in a molecule. The bond angle is different for different molecular geometry.

The Valence shell electron pair repulsion theory predicts the molecular geometry and shape of the given molecule by the number of lone pairs on central atom and number of atoms bonded to central atom.

(A) SO₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 1

<u>Therefore, the shape of SO₂ molecule is bent and the O-S-O bond angle is 119°.</u>

(B) BF₃ molecule

The number of atoms bonded to B = 3

Number of lone pairs on B = 0

<u>Therefore, the shape of BF₃ molecule is trigonal planar and the F-B-F bond angle is 120°.</u>

(C) SCl₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 2

<u>Therefore, the shape of SCl₂ molecule is bent and the Cl-S-Cl bond angle is 103°.</u>

(D) CO₂ molecule

The number of atoms bonded to C = 2

Number of lone pairs on C = 0

<u>Therefore, the shape of CO₂ molecule is linear and the O-C-O bond angle is 180°.</u>

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The number of atoms bonded to P = 3

Number of lone pairs on P = 1

<u>Therefore, the shape of PF₃ molecule is trigonal pyramidal and the F-P-F bond angle is 96.3°.</u>

(F) CH₄ molecule

The number of atoms bonded to C = 4

Number of lone pairs on C = 0

<u>Therefore, the shape of CH₄ molecule is tetrahedral and the H-C-H bond angle is 109.5°.</u>

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