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4 years ago

Consider the hydrocarbon below.

2 answers:

4 0

It is an Alkene because it has a double bond, so it’ll have “ene” at the end. The simplest Alkene has 2 carbons.

2 carbons = “eth”

Look at that! Two carbons! It must be “ethene”

Pachacha [2.7K]4 years ago

3 0

Answer: ethene

Explanation:

The representation of the hydrocarbon is:

H        H
\       /
C = C
/        \
H         H

So, the double C bond means it is an alkene.

The number of carbon atoms in the molecule is named with the proper prefix:

propa - is used for 3 carbon atoms
penta - is used for 5 carbon atoms
but - is used for 4 carbon atoms
etha - is use for 2 carbon atoms.

Therefore that alkene is name ethene

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How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?

GalinKa [24]

Answer:

700 mL of water

Explanation:

This is the perfect example of dilation calculations. Along with this concept we have a formula c = n ( solute ) / V ( solution ). Let us first solve for n by changing this equation to isolate the solute,

n ( KCL ) = 2.4 mol / L * 500 * 10 ^ - 3 L,

n ( KCL ) = 1.2 moles ( KCL )

Knowing the amount of moles of potassium chloride, we have to now identify how much is present in the target solution,

V = 1 .2 moles / ( 1.0 moles / L )

V = 1.2 L = 1200 mL

_______________________________________________________

Vadded = 1200 - 500 = 700 mL

<u><em>Hope that helps!</em></u>

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4 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:

KATRIN_1 [288]

Answer: $MgS$ , $MgBr_2$ , $V_2S_5$ and $VBr_5$ are four binary ionic compounds that could be formed.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Mg is having an oxidation state of +2 called as $Mg^{2+}$ cation and $S^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $MgS$ . Also $Mg^{2+}$ cation and $Br^{-}$ can combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $MgBr_2$ .

Also Vanadium is having an oxidation state of +5 called as $V^{5+}$ cation and $S^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $V_2S_5$ . Also $V^{5+}$ cation and $Br^{-}$ anion can combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $VBr_5$ .

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3 years ago

Consider the reaction, 2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g) When D is decreasing at 0.15 mol/Ls, how quickly is E decreasi

muminat

Answer:

0.023 mol/(L*s).

Explanation:

Equation of the reaction:

2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g)

Using stoichiometry, 2 moles of D reacts with 3 moles of E and 1 mole of F to give the above products.

1 mole of D will react with 3/2 moles of E.

Delta[D]/delta t = 0.15 mol/L.s

Delta[E]/delta t = (3/2) * 0.15 =

= 0.023 mol/(L*s).

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4 years ago

Which characteristic distinguishes an estuary form other bodies of water

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An estuary is partly enclosed and forms a transition zone between rivers and oceans/ seas

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3 years ago

Why does platinum metal make a good catalytic surface for reactant molecules?

d1i1m1o1n [39]

Answer:

it holds reactant molecules in a good position for then to react

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3 years ago