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RSB [31]
3 years ago
15

Consider the hydrocarbon below.

Chemistry
2 answers:
Ket [755]3 years ago
4 0
It is an Alkene because it has a double bond, so it’ll have “ene” at the end. The simplest Alkene has 2 carbons.

2 carbons = “eth”

Look at that! Two carbons! It must be “ethene”
Pachacha [2.7K]3 years ago
3 0
Answer: ethene

Explanation:

The representation of the hydrocarbon is:

H        H
  \       /
  C = C
  /        \
H         H

So, the double C bond means it is an alkene.

The number of  carbon atoms in the molecule is named with the proper prefix:

propa - is used for 3 carbon atoms
penta - is used for 5 carbon atoms
but - is used for 4 carbon atoms
etha - is use for 2 carbon atoms.

Therefore that alkene is name ethene
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A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw th
Ierofanga [76]

Answer:

H_{3}C--H_{3}C--CH_{3}--Br--CH_{3}

Explanation:

The steps involved in predicting the structure of the alkyl bromide compound are outlined below.

1) An examination of the product shows that the product could only be formed by a substitution reaction.

2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.

Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is H_{3}C--H_{3}C--CH_{3}--Br--CH_{3}. A pictorial diagram of the alkyl bromide compound is also attached.

8 0
3 years ago
Read 2 more answers
Why are food preservatives added to food?
nika2105 [10]
I believe it's gonna be B or C
3 0
3 years ago
Read 2 more answers
Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu
borishaifa [10]

Answer:

\large \boxed{\mathbf{1.36; 3.6 \times 10^{\mathbf{-9}}}\textbf{mol/L}}

Explanation:

The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.

1 .Calculate the hydronium ion concentration

We can use an ICE table to organize the calculations.

                    HF + H₂O ⇌ H₃O⁺ + F⁻

I/mol·L⁻¹:       2.7                   0       0

C/mol·L⁻¹:      -x                   +x      +x

E/mol·L⁻¹:   2.7 - x                 x        x

K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}] \text{F}^{-}]} {\text{[HF]}} = 7.2 \times 10^{-4}\\\\\dfrac{x^{2}}{2.7 - x} = 7.2 \times 10^{-4}\\\\\text{Check for negligibility of }x\\\\\dfrac{2.7}{7.2 \times 10^{-4}} = 4000 > 400\\\\\therefore x \ll 2.7\\\dfrac{x^{2}}{2.7} = 7.2 \times 10^{-4}\\\\x^{2} = 2.7 \times 7.2 \times 10^{-4} = 1.94 \times 10^{-3}\\x = 0.0441\\\text{[H$_{3}$O$^{+}$]}= \text{x mol$\cdot$L$^{-1}$} = \text{0.0441 mol$\cdot$L$^{-1}$}

2. Calculate the pH

\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{0.0441} = \large \boxed{\mathbf{1.36}}

3. Calculate [C₆H₅O⁻]

C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺

     2.7                         x        0.0441

K_{\text{a}} = \dfrac{0.0441x} {2.7} = 1.6 \times 10^{-10}\\\\0.0441x = 1.6 \times 10^{-10}\\x = \dfrac{1.6 \times 10^{-10}}{0.0441} = \mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}\\\text{The concentration of phenoxide ion is $\large \boxed{\mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}}$}

6 0
3 years ago
Which pair of atoms is held together by a covalent bond HCl LiCl NaCl KCl​
Luda [366]

Answer:

HCL

Explanation:

Covalent bond are formed between non metals so look for the pair of non metal atoms and this would be hydrogen chloride (HCL)

8 0
3 years ago
On many common appliances, there is an “O” or “I” on the power switch. What does each symbol mean?
Art [367]

"I" symbol means the current goes through the system (imagine the 'I' being a line, like a circuit connecting [power to the device]) "O" symbol means the current does not go through the system. ( the circle is an open circuit, having no power flowing through it
3 0
3 years ago
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