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svp [43]
3 years ago
6

The brown Haze that forms over Sunny cities like Los Angeles is called

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0
The brown Haze that forms over Sunny cities like Los Angeles is called smog. It <span> is a yellowish or blackish fog formed mainly by a mixture of pollutants in the atmosphere which consists of fine particles and ground level ozone.</span><span> Hope this answers the question.</span>
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determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass
Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

K_{f}or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             ΔT_{f} = i ×K_{f} ×m

T⁰-T_{s}  = i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water     in     kg}

in which,

ΔT_{f} = change in freezing point

ΔT_{s} = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T_{s} = 1 ×1.86°C/m ×\frac{30.7}{92.09g/mol * 0.376kg}

T_{s} = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

<h2 />

Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

#SPJ4

8 0
1 year ago
The following steps refer to various stages in transmission at a chemical synapse. 1. Neurotransmitter binds with receptors asso
Furkat [3]

Answer:

3,2,5,1,4

Explanation:

A chemical synapse begins when an (3)<em>action potential reaches the axon terminal depolarizing the membrane</em> leading to the opening of the voltage-gated Na+ channels, this Na+ ions will then depolarize the presynaptic membrane, opening the voltage-gated Ca2+ channels. (2)<em>Calcium ions then will initiate a cascade entering the neuron </em>that will lead to the fusion of synaptic vesicles with the presynaptic membrane (5)<em>causing the releasing of neurotransmitters into the synaptic cleft.</em> (1)<em>These neurotransmitter will diffuse across the synaptic place in order to bind to the receptors on the postsynaptic membrane,</em> (4)<em>particulary into the ligand-gated channels, opening them.</em>

I hope you find this information useful and interesting! Good luck!

7 0
3 years ago
The equilibrium concentrations for the reaction between N2 and O2 to form NO at a certain temperature are given in the table bel
MaRussiya [10]

Answer:

c

Explanation:

c is correct i believe

8 0
2 years ago
Carbon disulfide burns in oxygen to yield car- bon dioxide and sulfur dioxide according to the chemical equation cs2(l) 3 o2(g)
vampirchik [111]

Answer: Oxygen is the limiting reagent.

Explanation: CS_2(l)+3O_2(g)\rightarrow CO_2(g)+2SO_2(g)

As can be seen from the given balanced equation:

3 moles of O_2 reacts with 1 mole of CS_2

1.52 moles of O_2 reacts with=\frac{1}{3}\times 1.52=0.51moles of CS_2

Thus O_2 is the limiting reagent as it limits the formation of products. (0.91-0.51)= 0.40 moles of CS_2 will remain as such and thus  CS_2 is an excess reagent.

6 0
3 years ago
trace amounts of copper are required for good healt.but high concentrations of copper can be toxic.under what conditions might t
Andru [333]
For example, at atmospheric corrosion of copper:
2Cu + CO₂ + O₂ + H₂O = CuCO₃*Cu(OH)₂

and disolution of substances of copper in an acid condition:
CuCO₃*Cu(OH)₂(s) + 4HNO₃(aq) = 2Cu(NO₃)₂(aq) + CO₂(g) + 3H₂O(l)
CuCO₃*Cu(OH)₂(s) + 4H⁺ = 2Cu²⁺ + CO₂ + 3H₂O
3 0
3 years ago
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