Answer:
Step-by-step explanation:
a) circumference = diameter*pi
so, pi in circle A =25.12/8=3.14
pi in circle B = 9.42/3 =3.14
b) area of the circle =(diameter/2)^2*pi
so pi in circle A = 50.24/(8/2)^2=3.14
pi in circle B = 3.14
C) both the value of circle A and B are equivalent
Answer:
The correct answer is 12.8 J.
Step-by-step explanation:
To solve this problem, we must remember how to calculate the kinetic energy of an object.
The kinetic energy is represented by the formula K = 1/2 * m * v^2, where m represents the mass of the object and v represents the speed or velocity of the object. If we plug in the given values into the formula, we get:
K = 1/2 * m * v^2
K = (1/2) * (0.40) * (8.0)^2
Our first step is to square the velocity. After doing this step, we get the following:
K = (1/2) * (0.40) * (64)
Finally, we can perform the multiplication, to get:
K = 12.8
The unit for kinetic energy is joules, so the correct answer is 12.8 J.
Hope this helps!
If we take the perimeter of the park as being equivalent to the distance that Anwar walks, then we can calculate the number of blocks he walks and then multiply this by the width of each block, thus:
Number of blocks walked = 1 + 2 + 2 + 1 + 1 + 1 = 8
Distance walked = 8*300 = 2400 feet
(You could also draw a diagram to help present this in a visual way but it is not necessary)
Answer:
3 x-intercepts
Step-by-step explanation:
f(x) = x⁴ - 5x²
Answer:
Step-by-step explanation:
Given that that (X) the amount of time lapsed between consecutive trades on the New York Stock Exchange followed a normal distribution with a mean of 15 seconds.
i.e. X is normal with mean = 15 and unknown std deviation ![\sigma](https://tex.z-dn.net/?f=%5Csigma)
Given that![P(X](https://tex.z-dn.net/?f=P%28X%3C13%29%20%3D%207%25%20%3D%200.07)
i.e. P(![z](https://tex.z-dn.net/?f=z%3C%5Cfrac%7B13-15%7D%7B%5Csigma%7D%20%29%3D0.07)
z=-1.475 (from normal table)
Hence ![\frac{13-15}{\sigma}=-1.475\\\sigma = 1.356](https://tex.z-dn.net/?f=%5Cfrac%7B13-15%7D%7B%5Csigma%7D%3D-1.475%5C%5C%5Csigma%20%3D%201.356)
Using this we find P(X>17) = ![P(Z>\frac{17-15}{1.356} \\=P(Z>1.475)\\=0.5-0.428\\=0.072](https://tex.z-dn.net/?f=P%28Z%3E%5Cfrac%7B17-15%7D%7B1.356%7D%20%5C%5C%3DP%28Z%3E1.475%29%5C%5C%3D0.5-0.428%5C%5C%3D0.072)