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Vesnalui [34]
3 years ago
6

An object is dropped from a 45 m high building. At the same time, another object is thrown

Physics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

-92.33 (meaning the objects will not meet above the ground).

Explanation:

We can use the kinematic equation <em>displacement = initial velocity*time + 1/2*acceleration*time^2.</em>

We can plug in the known values of the 2 objects into the equation, where t is the time and x is the displacement:

x = 0*t + 1/2*(-9.8)*t^2+45

x = 8.5*t + 1/2*(-9.8)*t^2

We need to first solve for t to solve for x. Since both equations are equal to x, we can set them equal to each other and solve for t:

0*t + 1/2*(-9.8)*t^2+45 = 8.5*t + 1/2*(-9.8)*t^2

-4.9*t^2 +45 = 8.5*t + -4.9*t^2

45 = 8.5*t

t = 45/8.5 ≈5.294

Now, we can plug t as 5.294 into any of the equations above to solve for x:

x = 0*5.294 + 1/2*-9.8*(5.294)^2+45 ≈ -92.33

That means, the objects will not meet above the ground.

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Answer:

V=533.33 V

Explanation:

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Now by putting the values

C=\dfrac{8.85\times 10^{-12}\times 30\times 10^{-4}}{0.059\times 10^{-2}}

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An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.3 times the mass of the other. If
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Answer:

k_2 =3826.08 J

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Explanation:

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k_1 = \frac{1}{2} m_1v_1^2

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k_2 =3826.08 J

K_1 = 4973.91 J

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