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3 years ago

The Sun keeps all of the planets orbiting it because _____.

Physics

2 answers:

ArbitrLikvidat [17]3 years ago

5 0

Answer:

The answer is the law of universal gravitation states that an increase in mass causes an increase in gravitational force

Explanation:

The law of universal gravitation is a physical law that describes the gravitational interaction between different bodies with mass. It was formulated by Isaac Newton and establishes a proportional relationship of the force with which two objects with mass are attracted, that is, the force with which two bodies are attracted had to be proportional to the product of their mass divided by the distance between them squared.

Sergeeva-Olga [200]3 years ago

4 0

a) the law of universal gravitation states that an increase in mass causes an increase in gravitational force

hope this helps!

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A 1800 kg car moving south at 17.5 m/s collide with a 2800 kg car moving north. The cars stick together and move as a unit after

weqwewe [10]

Answer:

v₀₂ = -2.67 m / s

Explanation:

Let's use the conservation of the moment, for this we define a system formed by the two cars.

Consider the north direction as positive and the subscript 1 will be used for car 1 and the subscript 2 for the second car

Initial instant. Before the crash

p₀ = -m₁ v₀₁ + m₂ v₀₂

Final moment. Right after the crash

p_f = (m₁ + m₂) v

p₀ = p_f

-m₁ $v_{o1}$ + m₂ v_{o2} = (m₁ + m2) v_{f}

v₀₂ = $\frac{(m_1 +m_2) v }{m_2}$ + $\frac{m_1 v_{o1} }{m_{1} }$

let's calculate

v₀₂ = $\frac{(1800 +2800) 5.22 + 1800 (-17.5)}{2800}$

v₀₂ = -2.67 m / s

the negative sign indicates that the carriage moves in the opposite direction of the temperies

8 0

3 years ago

Which statement BEST describes the benefits of muscular fitness training?

Hoochie [10]

I think it is A <span>High levels of muscular fitness can improve your self-image and improve or prevent chronic diseases such as diabetes, osteoporosis, and cardiovascular disease.</span>

6 0

4 years ago

2 Select the correct answer. Javed suffers from a severe food allergy. Which device should Javed always carry? A. inhaler B. epi

Slav-nsk [51]

The best answer would be:

B. Epi pen

Here is more about it:

An epi pen injects epinephrine into the body to counteract the effects of an allergic reaction. Epinephrine helps narrow blood vessels and open up the airways. This can be used for food allergies, insect bites, and some other allergens. It is very effective and immediately works, but it is short-lived, so seeking medical attention after is still needed.

4 0

3 years ago

Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the

Over [174]

Answer:

Part a)

$a= 0.32 m/s^2$

Part b)

$F_c = 3.6 N$

Part c)

$F_c = 5.5 N$

Explanation:

Part a)

As we know that the friction force on two boxes is given as

$F_f = \mu m_a g + \mu m_b g$

$F_f = 0.02(10.6 + 7)9.81$

$F_f = 3.45 N$

Now we know by Newton's II law

$F_{net} = ma$

so we have

$F_p - F_f = (m_a + m_b) a$

$9.1 - 3.45 = (10.6 + 7) a$

$a = \frac{5.65}{17.6}$

$a= 0.32 m/s^2$

Part b)

For block B we know that net force on it will push it forward with same acceleration so we have

$F_c - F_f = m_b a$

$F_c = \mu m_b g + m_b a$

$F_c = 0.02(7)(9.8) + 7(0.32)$

$F_c = 3.6 N$

Part c)

If Alex push from other side then also the acceleration will be same

So for box B we can say that Net force is given as

$F_p - F_f - F_c = m_b a$

$9.1 - 0.02(7)(9.8) - F_c = 7(0.32)$

$F_c = 9.1 - 0.02 (7)(9.8) - 7(0.32)$

$F_c = 5.5 N$

3 0

3 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 78.5 m/s. Th

Andrews [41]

Answer:

FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

Explanation:

First you have to consider that the Ford Thunderbird (FT) follows a rectilinear motion with varying acceleration, while Mercedez Benz (MB) has a constant velocity (no acceleration). So if you finde the time spent by FT in each section, and the distance, then you will find the distance for MB.

1) Vf² = Vi² + 2ad, where Vf: final velocity, Vi: ionitial velocity, a: acceleration and d: distance.

For the first portion (0 m/s)² = (78.5 m/s)² + 2a(250 m) ⇒

-(78.5 m/s)² / 2(250m) = a ⇒ a = -12.3 m/s².

Now, you can find the corresponding time for this section with the following formule: Vf = Vi + at ⇒ 0 m/s = 78.5 m/s + (-12.3 m/s²) t

⇒ t= (-78.5 m/s)/ (-12.3 m/s²) ⇒ t= 6.4 seconds.

2) Then FT spent 5 seconds in the pit.

3) The the FT accelerates until reach 78.5 m/s again in a distance of 370 m.

Vf² = Vi² + 2ad ⇒ (78.5 m/s)² = (0 m/s)² + 2a(370 m)

⇒ (78.5 m/s)²/ 2(370 m) = a ⇒ a = 8.3 m/s²

Then, Vf = Vi + at ⇒ 78.5 m/s = 0 m/2 + (8.3 m/s²) t

⇒ (78.5 m/s)/(8.3 m/s²) = t ⇒ t = 9.5 seconds.

4) Summarizing, the FT moves 620 meters (250 + 370 mts) in 20.9 seconds ( 6.4 s + 5 s + 9.5 s).

5) During this time, MB moves

Velocity = distance/ time ⇒ Velocity x time = Distance

⇒ Distance = (78.5 m/s) x (20.9 seconds) ⇒ Distance = 1640.6 meters

6) Finally, the FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

3 0

3 years ago