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Deffense [45]
3 years ago
11

A ladybug sits 10.8 cm from the center of a beatles music album spinning at 33.33 rpm. What is the maximum velocity (in m/s) of

its shadow on the wall behind the turntable, if illuminated parallel to the record by the parallel rays of the setting sun?
Physics
2 answers:
snow_lady [41]3 years ago
7 0

Answer:

The maximum velocity is 0.377 m/s

Explanation:

Please, the solution is in the Word file attached

Download docx
trapecia [35]3 years ago
5 0

solution;

The max^m liner velocity v_{max}=r_{w}\\here r is the radius of circular track first convert rpm to radian pedr second\\1rpm=\frac{2\pi }{60}rad/s\\33.33rpm=\frac{2\pi }{60}\times33.33rad/s\\3.49rad/s\\substitute 10.8cm for r and 3.49 ras/s for w\\v_{max}=(0.108m)(3.49rad/s)\\0.377m/s\\hence, the max^m velocity of the shadow of the ladybug is 0.377m/s

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15) On a cold day, you take in 4.2 L (i.e., 4.2 x 10-3 m3) of air into your lungs at a temperature of 0°C. If you hold your brea
Rudiy27

Answer:

4.8L ( i.e 4.8 x 10^-3 m3)

Explanation:

Step 1:

Data obtained from the question.

Initial volume (V1) = 4.2L

Initial temperature (T1) = 0°C

Final temperature (T2) = 37°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 0°C = 0°C + 273 = 273K

T2 = 37°C = 37°C + 273 = 310K

Step 3:

Determination of the final volume.

Since the pressure is constant,

Charles' Law equation will be applied as shown below:

V1 /T1 = V2/T2

4.2/273 = V2 /310

Cross multiply to express in linear form

273 x V2 = 4.2 x 310

Divide both side by 273

V2 = (4.2 x 310)/273

V2 = 4.8L ( i.e 4.8 x 10^-3 m3)

Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)

3 0
3 years ago
Two students race up a flight of steps together. "Student A" reaches the top of the steps 2 seconds ahead of
oksano4ka [1.4K]
Um student a because they were there a few seconds ahead
3 0
3 years ago
If you jog at a speed of 1.5m/s for 20 seconds how far di you travel
Harlamova29_29 [7]

Answer: 30m

Explanation:

Given:

Speed: 1.5m/s

Time: 20 seconds

Distance = speed × time

Distance = 1.5 × 20

= 30m

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3 0
3 years ago
This should be correct
sweet-ann [11.9K]

Maybe it is, maybe it isn't.  We can't tell, until we see what "this" is. 

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5 0
3 years ago
3. Maverick and Goose are flying a training mission in their F-14. They are
Elanso [62]

Answer:

A. The bomb will take <em>17.5 seconds </em>to hit the ground

B. The bomb will land <em>12040 meters </em>on the ground ahead from where they released it

Explanation:

Maverick and Goose are flying at an initial height of y_0=1500m, and their speed is v=688 m/s

When they release the bomb, it will initially have the same height and speed as the plane. Then it will describe a free fall horizontal movement

The equation for the height y with respect to ground in a horizontal movement (no friction) is

y=y_0 - \frac{gt^2}{2}    [1]

With g equal to the acceleration of gravity of our planet and t the time measured with respect to the moment the bomb was released

The height will be zero when the bomb lands on ground, so if we set y=0 we can find the flight time

The range (horizontal displacement) of the bomb x is

x = v.t     [2]

Since the bomb won't have any friction, its horizontal component of the speed won't change. We need to find t from the equation [1] and replace it in equation [2]:

Setting y=0 and isolating t we get

t=\sqrt{\frac{2y_0}{g}}

Since we have y_0=1500m

t=\sqrt{\frac{2(1500)}{9.8}}

t=17.5 sec

Replacing in [2]

x = 688\ m/sec \ (17.5sec)

x = 12040\ m

A. The bomb will take 17.5 seconds to hit the ground

B. The bomb will land 12040 meters on the ground ahead from where they released it

6 0
3 years ago
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