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2 years ago

PLEASE HELP ME WITH THIS ONE QUESTION

Physics

1 answer:

sdas [7]2 years ago

6 0

Answer:

0.34 m

Explanation:

From the question,

v = λf................ Equation 1

Where v = speed of sound, f = frequency, λ = Wave length

Make λ the subject of the equation

λ = v/f............... Equation 2

Given: v = 340 m/s, f = 500 Hz.

Substitute these values into equation 2

λ = 340/500

λ = 0.68 m

But, the distance between a point of rarefaction and the next compression point, in the resulting sound is half wave length

Therefore,

λ/2 = 0.68/2

λ/2 = 0.34 m

Hence, the distance between a point of rarefaction and the next compression point, in the resulting sound is 0.34 m

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Gala2k [10]

Answer:

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Explanation:

Given that

speed of the vehicle, v = 95 km/h

time of inattentiveness, t = 2 s

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Since we have the speed in km/h and the time in s, it would be best if we converted one of them to make sure we have all units in the same rank.

95 km/h = 95 * 1000/3600 m/s

95 km/h = 95000/3600 m/s

95 km/h = 26.38 m/s

Now, we use our derived speed in m/s

Speed of a moving vehicle is given by,

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t = time spent, in s

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distance travelled, s = 52.7 m

therefore, during this inattentive period, 52.7 m was travelled.

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3 years ago

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2 years ago

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