Answer:
2.72 m/s
Explanation:
In 3 meters a person running 0.5 m/s accelerates 1.2 m/s².
It means,
Distance, s = 3 m
Initial velocity, u = 0.5 m/s
Acceleration, a = 1.2 m/s²
We need to find the final velocity of the person. Using equation of motion to find it as follows :

So, the final velocity of the person is 2.72 m/s.
She uses 0 power because she simply has no gas left. She used all of it getting a 50 pc McDonald’s nugget with a side of ranch and a medium fry and a large water.
<u>Halfway</u><u> between the like poles of two magnets, because the field lines bend away and do not enter this area.</u>
How does a magnetic field diagram show where the field is strongest?
- The magnetic field lines do not ever cross.
- The lines include arrowheads to indicate the direction of the force exerted by a magnetic north pole.
- The closer the lines are to the poles, the stronger the magnetic field (thus the magnetic field from a bar magnet is highest closest to the poles).
Where is magnetic field the strongest and weakest on a magnet?
- The bar magnet's magnetic field is strongest at its core and weakest between its two poles.
- The magnetic field lines are densest immediately outside the bar magnet and least dense in the core.
Which two locations on the magnet would have the greatest attractive forces?
- Inside the magnet itself, the field lines run from the south pole to the north pole.
- The magnetic field is strongest in areas of greatest density of magnetic field lines, or areas of the greatest magnetic flux density.
Learn more about magnetic field
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Answer:
time required after impact for a puck is 2.18 seconds
Explanation:
given data
mass = 30 g = 0.03 kg
diameter = 100 mm = 0.1 m
thick = 0.1 mm = 1 ×
m
dynamic viscosity = 1.75 ×
Ns/m²
air temperature = 15°C
to find out
time required after impact for a puck to lose 10%
solution
we know velocity varies here 0 to v
we consider here initial velocity = v
so final velocity = 0.9v
so change in velocity is du = v
and clearance dy = h
and shear stress acting on surface is here express as
= µ 
so
= µ
............1
put here value
= 1.75×
× 
= 0.175 v
and
area between air and puck is given by
Area =
area =
area = 7.85 ×
m²
so
force on puck is express as
Force = × area
force = 0.175 v × 7.85 × 
force = 1.374 ×
v
and now apply newton second law
force = mass × acceleration
- force = 
- 1.374 ×
v = 
t = 
time = 2.18
so time required after impact for a puck is 2.18 seconds
Answer:
<u>A:cool fluid sinks</u>
<u>B:warm fluid rises</u>
<u>C:convection current</u>
Explanation:
Just took the assessment!!