What is 1 21/50 in a percentage?

PLEASE ANSWER THIS QUESTION! I BEG OF YOU

Law Incorporation [45]

The difference between the rate of change of B and the rate of change of A is 15.

<h3>How to get the difference in the rates of change?</h3>

First, we need to get the two rates of change.

We have two linear functions.

A: y = 35*x

For function A the rate of change is the slope, wich is 35.

Function B is graphed.

Remember that if a line passes through two points (x₁, y₁) and (x₂,y₂) then the slope is:

$a = \frac{y_2 - y_1}{x_2 - x_1}$

In the graph, we can see that line B passes through (0, 0) and (1, 50), then the slope is:

$a = \frac{50 - 0}{1 - 0} = 50$

Then the rate of change of B is 50.

The difference between the rates of change is:

diff = 50 - 35 = 15

If you want to learn more about rates of change:

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5 0

2 years ago

Circle X with a radius of 6 units and circle Y with a radius of 2 units are shown. Which steps would prove the circles similar?

SSSSS [86.1K]

Answer:

See bolded below.

Step-by-step explanation:

Take a look at the attachment below. It represents circle x and y, with respect to each of their radii. In each of the options we are given, we would have to translate and dilate the circles, by a fixed scale factor -

Now the first thing one would do is translate the circles so that they share a common center point, or in other words the center of one circle rests on the edge of the other circle. That way when dilating circle y, it may fit into circle x as it expands.

The second point is how much this smaller circle ( circle y ) has to expand. The radius of circle y being 2, has to increase by 3 times the value to equal the radius of circle x, and hence has to dilate by a scale factor of 3 as to match circle x,

<u><em>Solution = " Translate the circles so the center of one circle rests on the edge of the other circle, and dilate circle Y by a scale factor of 3 " / Option D</em></u>

3 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP HURRY

bulgar [2K]

Answer: The amount she pays for admission

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Question

EleoNora [17]

Answer:

students in the drama club: 57

students in the yearbook club: 44

Step-by-step explanation:

101 - 13 = 88

88 / 2 = 44

101 - 44 = 57

44 in the drama club and 57 in the yearbook club

5 0

2 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame

lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678$

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{207.9 - 208}{0.1678}$

$Z = -0.6$

$Z = -0.6$ has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0

3 years ago