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andreyandreev [35.5K]
3 years ago
7

Two identical objects A and B fall from rest from different heights to the ground. If object B takes twice as long as object A t

o reach the ground, what is the ratio of the heights from which A and B fell
Physics
1 answer:
Yuki888 [10]3 years ago
7 0

Answer:

1:4

Explanation:

We have, two identical objects A and B fall from rest from different heights to the ground.

Object B takes twice as long as object A to reach the ground. It is required to find the ratio of the heights from which A and B fell. Let h_A\ \text{and}\ h_B are the height for A and B respectively. So,

\dfrac{h_A}{h_B}=\dfrac{(1/2)gt_A^2}{(1/2)gt_B^2}\\\\\dfrac{h_A}{h_B}=\dfrac{t_A^2}{t_B^2}

We have,

t_B=2t_A

So,

\dfrac{h_A}{h_B}=\dfrac{t_A^2}{(2t_B)^2}\\\\\dfrac{h_A}{h_B}=\dfrac{1}{4}

So, the ratio of the heights from which A and B fell is 1:4.

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q = -k[(T₂ - T₁)/Δx]

Where, k is the thermal conductivity of the metal, ΔT is the temperature difference and Δx is the thick.

With Δx = 11 mm = 11x10⁻³m, T₂ = 350°C and T₁ = 110°C, and k = 53.0 W/m-K:

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