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Aleksandr [31]
3 years ago
12

Help me please!!!!!!!!!!!

Mathematics
1 answer:
skad [1K]3 years ago
3 0

Solution: x \ge 11

Graph: Closed circle at 11, shading to the right

======================================================

Work Shown:

x+7 \ge 18\\\\x+7-7 \ge 18-7\\\\x \ge 11

In the second step, I subtracted 7 from both sides to undo the "plus 7".

To graph this, we place a closed or filled in circle at 11. Then we shade to the right. The endpoint x = 11 is included as part of the solution set, which is why we use a closed circle instead of an open hole.

This visually describes all values that are equal to 11 or larger than 11.

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the area of a room in a dollhouse is 1248 square inches. the width of the room is 8 inches. how long is the room
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Answer:

According to the rule of 72, the doubling time for this interest rate is 8 years.

The exact doubling time of this amount is 8.04 years.

Step-by-step explanation:

Sometimes, the compound interest formula is quite complex to be solved, so the result can be estimated by the rule of 72.

By the rule of 72, we have that the doubling time D is given by:

D = \frac{72}{Interest Rate}

The interest rate is in %.

In our exercise, the interest rate is 9%. So, by the rule of 72:

D = \frac{72}{9} = 8.

According to the rule of 72, the doubling time for this interest rate is 8 years.

Exact answer:

The exact answer is going to be found using the compound interest formula.

A = P(1 + \frac{r}{n})^{nt}

In which A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

is double the initial amount, double the principal.

A = 2P

r = 0.09

The interest is compounded anually, so n = 1

A = P(1 + \frac{r}{n})^{nt}

2P = P(1 + \frac{0.09}{1})^{t}

2 = (1.09)^{t}

Now, we apply the following log propriety:

\log_{a} a^{n} = n

So:

\log_{1.09}(1.09)^{t} = \log_{1.09} 2

t = 8.04

The exact doubling time of this amount is 8.04 years.

4 0
3 years ago
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