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MakcuM [25]
3 years ago
8

Which of the following are correct statements? Check all that apply. A. An electron is a positively charged particle that orbits

the nucleus. B. A proton is a positively charged particle in the nucleus. C. An electron is a negatively charged particle in the nucleus. D. A neutron is a neutral particle.
Physics
1 answer:
AVprozaik [17]3 years ago
7 0
B is the correct answer but also D is correct

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HELP PLEASEE!
patriot [66]

protons and nuetrons are all attracted to each another as the result of the strong nuclear force

4 0
4 years ago
An electric current flows through a parallel circuit. Which units tell you about the amount of electrons traveling in the circui
kompoz [17]

'Ampere' is the unit of current.  That's the rate at which
electrons travel in the circuit ... the number of electrons
every second.  If you wanted the actual amount or number
of electrons, you'd need to know the length of time too.

It doesn't matter whether we're talking about a parallel or
series circuit.
8 0
4 years ago
which would be a better predictor of increase in force of contraction, change in semg amplitude of spikes or change in semg freq
zaharov [31]

The better predictor of increase in force of contraction, change in semg amplitude of spikes.

<h3>What is force?</h3>

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Given that in the question the  better predictor of increase in force of contraction, change in semg amplitude of spikes or change in semg frequency of spikes.

The better predictor of increase in force of contraction, change in semg amplitude of spikes.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ1

7 0
1 year ago
Define average velocity and instantaneous velocity when are they same ​
Vlada [557]

Answer:

Look to the explanation

Explanation:

<u><em>Average velocity:</em></u> is the average rate of change of displacement with

respect to time

Average velocity is a measure for distance traveled in a given time

We can calculate the average velocity by the rule v=\frac{s}{t}

where s is the displacement and t is the time

<u><em>Instantaneous velocity:</em></u> is the velocity of an object in motion at a

specific point (x , t)

instantaneous velocity is the limit of velocity as the change in time

approaches zero

We can calculate the instantaneous velocity by the rule v=\frac{ds}{dt}

<u>Average velocity</u> is <u>equal</u> to the <u>instantaneous velocity</u> when

<u>acceleration</u> is <u>zero</u>

5 0
3 years ago
Two electrons are at rest and separated by a distance of 4.32 × 10-10 m. When they are released they accelerate away from each o
sasho [114]

Answer:

Speed of electron when their separation increased by a factor of 4.10 is 9.41 x 10⁵ m/s .

Explanation:

The electric potential energy is given by the relation :

U = \frac{kq_{1}q_{2}  }{r}

Here q₁ and q₂ are the two charge particles and r is the distance between them and k is electric constant.

In this case, there are two electrons which are separated by the distance 4.32 x 10⁻¹⁰ m.

Let e be the electron charge and r₁ be the distance between them. Then, the initial electric potential energy is :

U_{1}  = \frac{ke^{2}   }{r_{1} }

Now, the distance between the electrons increases by the factor of 4.10. Let r₂ be the new distance between them i.e. r₂ = 4.10 r₁.

Thus, the new electric potential energy is :

U_{2}  = \frac{ke^{2}   }{r_{2} }=\frac{ke^{2}   }{4.10r_{1} }

Applying law of conservation of energy :

ΔU  = ΔK

Here ΔU is change in electric potential energy and ΔK is change in kinetic energy.

( U₁  - U₂ ) = ( K₂ - K₁ )

Here K₂ and K₁ are initial and final kinetic energy of electron.

Since, the electron initially is at rest, so its initial kinetic energy is zero. Thus, the above equation becomes:

K₂ = U₁ - U₂

\frac{1}{2}mv^{2}=\frac{ke^{2}   }{r_{1} }- \frac{ke^{2}   }{4.10r_{1} }

Here m and v are the mass and final speed of electron respectively.

v^{2}=\frac{2}{m} \frac{ke^{2}   }{r_{1} }(1- \frac{1  }{4.10 })

Substitute 9.1 x 10⁻³¹ kg for m, 9 x 10⁹ N m² C⁻² for k, 1.6 x 10⁻¹⁹ C for e and 4.32 x 10⁻¹⁰ m for r₁ in the above equation.

v^{2}=\frac{2}{9.1\times10^{-31} } \frac{9\times10^{9}\times(1.6\times10^{-19})^{2}   }{4.32\times10^{-10} }(1- \frac{1  }{4.10 })

v^{2}=8.86\times10^{11}

v = 9.41 x 10⁵ m/s

5 0
3 years ago
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