The answer is c 1386j
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Complete question:
if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.
Answer:
The mutual force between the two point charges is 319.64 N
Explanation:
Given;
distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m
value of the charges, q₁ and q₂ = 2 μC and - μ4 C
Apply Coulomb's law;

where;
F is the force of attraction between the two charges
|q₁| and |q₂| are the magnitude of the two charges
r is the distance between the two charges
k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

Therefore, the mutual force between the two point charges is 319.64 N
Moon, earth, sun solar system, galaxy, universe
Answer:
J for impulse
t for time
F for force
formula is J=F×t
Explanation:
putting values in eqs after rearranging
we need to find force so
F=J ÷t
F=400÷15
=26.67
=27(rounded off)
27N is the Force applied.
Answer:
1: 6.18 cm
2: 52.5609 degrees
Explanation:
We have the pendulum speed at the origin, and in that moment, all energy is kinetic, so we can calculate the pendulum energy by:
Ec = 0.5*m*v^2 = 0.5*0.015*1.1^2 = 0.0091 J
Now with that energy, we can calculate the height the pendulum will reach, as in that moment, the kinetic energy is totally converted to gravitational potencial energy:
Eg = m*g*h = 0.0091
0.015 * 9.81 * h = 0.0091
h = 0.0091 / (0.015 * 9.81 ) = 0.0618 m = 6.18 cm
Looking at the image attached, we can see that the pendulum will form a triangle, and one of the cathetus will be the length of the pendulum minus the height it went up, and the hypotenusa will be the pendulum length.
So, we know that the sine of the angle will be the division between the opposite cathetus and the hypotenusa:
sin(angle) = (30-6.18)/30 = 23.82/30 = 0.794 -> angle = 52.5609 degrees