Answer:
2.95 g of CH₄
Explanation:
To start this, we determine the equation:
4H₂ + CO₂ → CH₄ + 2H₂O
4 moles of hydrogen react to 1 mol of carbon dioxide in order to produce 1 mol of methane and 2 moles of water.
To determine the limiting reactant, we need to know the moles of each reactant.
8.1 g . 1 mol/ 44g = 0.184 moles of carbon dioxide
2.3 g . 1mol / 2g = 1.15 moles of hydrogen
4 moles of hydrogen react to 1 mol of CO₂
Then, 1.15 moles may react to (1.15 . 1) /4 = 0.2875 moles
We only have 0.184 moles of CO₂, so this is the limiting reactant. Not enough CO₂ to complete the 0.2875 moles that are needed.
Ratio is 1:1. 1 mol of CO₂ produces 1 mol of methane
Then, 0.184 moles of CO₂ will produce 0.184 moles of CH₄
We convert moles to mass: 0.184 mol . 16 g /mol = 2.95 g
Explanation:
The given data is as follows.
Volume = 1 L, Concentration of Ca = 5 ppm or 5 mg/L
As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.
Hence, calculate molarity of calcium as follows.
Molarity of Ca = 
= 
Molarity of Ca = 
Hence, molarity of 
is . Since, volume is same so, moles of calcium chloride will be 
.
Thus, we can conclude that mass of will be as follows.
(molar mass of = 110.984 g/mol)
= 0.0138 g
Thus, we can conclude that mass of is 0.0138 g.
When we have the balanced reaction equation is:
H2(g) + CO2(g) ↔ H2O(g) + CO (g)
a) first, to calculate ΔG° for the reaction:
we will use this formula:
ΔG° = -RT㏑Kp
when R is R- rydberg constant = 8.314J/mol.K
and T is the temperature in Kelvin = 2000 K
and Kp = 4.4
so, by substitution:
ΔG° = - 8.314 *2000 *㏑4.4
= - 24624 J/mol = - 24.6 KJ/mol
b) to calculate ΔG so, we will use this formula:
ΔG = ΔG° + RT㏑Qp
So we need first, to get Qp from the reaction equation:
when Qp = P products / P reactants
= PH2O*PCO / PH2 * PCO2
= (0.66 atm * 1.2 atm) / (0.25 * 0.78)
= 4.1
so by substitution:
ΔG = -24624 + 8.314*2000*㏑4.1
= -1162 J/mol = - 1.16 KJ/mol
Condensation is a chemical reaction in which two molecules are combined together and as a product formed a large molecule. There is also loss of small molecules in the condensation reaction. And mostly the functional groups combined in the reaction.
The other name for a condensation reaction is dehydration. As there is loss of molecule in condensation reaction, when that molecule is water it is said to be dehydration.
Group 1-lose 1; Group 2-lose 2; Group 13-lose 3; Group 16-gain 2; Group 17-gain 1; Group 18-gain 0
