Exactly 0.2220 g of pure Na2CO3 was dissolved in 100.0 mL of 0.0731 M HCl. (a) What mass in grams of CO2 was evolved
1 answer:
This problem is providing information about a chemical reaction between sodium carbonate and hydrochloric acid. Thus, the mass of evolved carbon dioxide is required and found to be 0.0922 g according to:
<h3>Stoichiometry:</h3>
In chemistry, stoichiometry is a tool that allows us to perform mole-mass calculations based on proportional factors involving the balanced chemical equation, molar masses and mole ratios. In such a way, for the reaction in this problem, we write:
In such a way, since both HCl and Na2CO3 are given, we calculate the grams of CO2 produced by each one, to identify the limiting reactant, according to the 2:1 and 1:1 mole ratios the reactants have with CO2 respectively:
Thus, since Na2CO3 produce the smallest amount of CO2, we infer it is the limiting reactant and therefore the correct produced amount is 0.0922 g.
Learn more about stoichiometry: brainly.com/question/9743981
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Answer: 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.
Explanation:
According to the dilution law,
where,
= concentration of stock solution = 12.0 M
= volume of stock solution = ?
= concentration of diluted solution= 6.00 M
= volume of diluted acid solution = 500 ml
Putting in the values we get:
Thus 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.